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JulsSmile [24]
3 years ago
8

In a collision, the __________ collision is when an unsecured driver strikes the inside of the vehicle.

Physics
2 answers:
zaharov [31]3 years ago
6 0
In a collision, the second collision is when an unsecured driver strikes the inside of the vehicle. It is a collision that happens between an occupant of a vehicle and the vehicle he is riding during the impact. The first collision would be the collision of the vehicle and the other object.
Leokris [45]3 years ago
5 0

Answer:

In a collision, the <em><u>SECOND</u></em> collision is when an unsecured driver strikes the inside of the vehicle.

Explanation:

When driver in the car is unsecured then it means that the driver is not having his safety seat belt.

Now when collision occurs between the car and some other object then due to the property of inertia of driver it has tendency to move in the direction of his motion.

So the driver will continue his motion and collide with other parts of the car and due to this he may got injured.

So in any car collision there are two types of collision

first is the collision of car with other objects

second collision is between car and the driver inside the car

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These diagrams show two atoms of fluorine and an atom of magnesium.
Bezzdna [24]

the answer is D. A magnesium atom donates two electrons to the fluorine atoms → Each fluorine atom accepts one of the electrons → The magnesium atom becomes a +2 ion → Each fluorine atom becomes a -1 ion

because magnesium only has 2 valence electrons, and it would be easier to lose electrons rather gain.

i just took the test, its right.


4 0
3 years ago
Read 2 more answers
A 6.0 m wire with a mass of 50 g, is under tension. A transverse wave, for which the frequency is 810 Hz, the wavelength is 0.40
MrRissso [65]

Answer:

a) t = 0.0185 s = 18.5 ms

b) T = 874.8 N

Explanation:

a)

First we find the seed of wave:

v = fλ

where,

v = speed of wave

f = frequency = 810 Hz

λ = wavelength = 0.4 m

Therefore,

v = (810 Hz)(0.4 m)

v = 324 m/s

Now,

v = L/t

where,

L = length of wire = 6 m

t = time taken by wave to travel length of wire

Therefore,

324 m/s = 6 m/t

t = (6 m)/(324 m/s)

<u>t = 0.0185 s = 18.5 ms</u>

<u></u>

b)

From the formula of fundamental frquency, we know that:

Fundamental Frequency = v/2L = (1/2L)(√T/μ)

v = √(T/μ)

where,

T = tension in string

μ = linear mass density of wire = m/L = 0.05 kg/6 m = 8.33 x 10⁻³ k gm⁻¹

Therefore,

324 m/s = √(T/8.33 x 10⁻³ k gm⁻¹)

(324 m/s)² = T/8.33 x 10⁻³ k gm⁻¹

<u>T = 874.8 N</u>

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3 years ago
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Answer:

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Explanation:

The object that have largest mass will   have largest inertia as well as largest momentum.

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