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ss7ja [257]
3 years ago
8

A 55.9 g sample of water at 99.2 °c is placed in a constant pressure calorimeter. then, 23.9 g of zinc metal at 21.1 °c is added

to the water and the temperature drops to 96.9 °c. what is the specific heat capacity of the zinc metal measured in this experiment?
Chemistry
1 answer:
Veronika [31]3 years ago
4 0
<span>Heat released by the water: mass * specific heat * ΔT

Heat released by the water = 55.9 g * 1 cal / (°C g) * (99.2 - 96.9 )°C

Heat absorbed by the zinc metal = mass * specifi heat * ΔT

Heat absorbed by the zinc metal =  23.9 g * Cp * (96.9 - 21.1) °C

Heat absorbed by zinc metal = heat released by water

=> 23.9 * Cp * 75.8 = 55.9 * 1 * 2.3

=> Cp = 128.57 / 1811.62 = 0.0071 cal / (g°C)

Answer: 0.0071 cal / (g°C)
</span>
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The total number of ions in 38.1 g of SrF₂ is 5.479 x 10²³.

<h3>What are ions?</h3>

Ions are the elements with a charge on them. It happens when they share electrons with other atoms to form a compound.

We have to calculate the total number of ions in 38.1 g of .

The molar mass of SrF₂ = 125.62 g/mol

The number of moles = 38.1 g of  1.0 mol / 125.62  = 0.30329 moles

Given that, total moles of SrF₂ ions in  = 1.0 mol of + 2.0 moles of  = 3.0 moles

Total moles of ions in 0.30329 moles of

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