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3 years ago

Use the reaction N2(g) + 3H2(g) 2NH3(g) to answer the following questions

Chemistry

1 answer:

Veronika [31]3 years ago

5 0

Answer:

][H

]

[NH

]

+3H

⇌2NH

(1.5×10

−2

)(3×10

−2

)

(1.2×10

−2

)

1.5×10

−2

×27×10

−6

1.44×10

−4

40.5×10

−4

1.44

=0.035×10

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Which of the following below is the complete ionic equation of the reaction: Calcium nitrate and sodium sulfide solutions react

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To find the net ionic equation we must first write the balanced equation for the reaction. We must bear in mind that the reagents Ca(NO3)2 and Na2S are in the aqueous state and as product we will have CaS in the solid state, since it is not soluble in water and NaNO3 in the aqueous state.

The balanced equation of the reaction will be:

$Ca(NO_3)_{2(aq)}+Na_2S_{(aq)}\rightarrow CaS_{(s)}+2NaNO_{3(aq)}$

Ca(NO3)2(aq) + → Ca(aq) + 2Na(s)NO3Now, c(aq)ompounds in the aqueous state can be written in their ionic form, so the reaction will transform into:Na2S +

$Ca_{(aq)}^{2+}+2(NO_3)_{(aq)}^-+2Na_{(aq)}^++S_{(aq)}^{2-}\operatorname{\rightarrow}CaS_{(s)}+2Na_{(aq)}^++2NO^-_{3(aq)}$

So, the answer will be option A

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1 year ago

if 2.22 moles of ammonia (NH3) decomposes according to the reaction shown how many moles of hydrogen (H2) are formed?

kirill [66]

Answer:

five(5) hydrogen are formed

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3 years ago

Drinking water may contain a low concentration of lead ion (Pb2 ) due to corrosion of old lead pipes. The EPA has determined tha

Lynna [10]

Answer:

3.861x10⁻⁹ mol Pb⁺²

Explanation:

We can define ppm as mg of Pb²⁺ per liter of water.

We calculate the mass of lead ion in 100 mL of water:

100.0 mL ⇒ 100.0 / 1000 = 0.100 L

0.100 L * 0.0080 ppm = 8x10⁻⁴ mg Pb⁺²

Now we convert mass of lead to moles, using its molar mass:

8x10⁻⁴ mg ⇒ 8x10⁻⁴ / 1000 = 8x10⁻⁷ g

8x10⁻⁷ g Pb²⁺ ÷ 207.2 g/mol = 3.861x10⁻⁹ mol Pb⁺²

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3 years ago

3. Identify the oxidizing agent in each of the fol-

Oxana [17]

Answer:

Explanation:

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

a) Cu²⁺ (aq) + Mg(s) + Cu(s) + Mg²⁺(aq)

Copper is oxidizing agent it accept two electrons from magnesium and oxidize the Mg and itself get reduced.

b) Fe₂O₃(s) + 3CO(g) → 2Fe(l) + 3CO₂(g)

In this reaction iron is oxidizing agent because iron itself reduced from +3 to 0.

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3 years ago

In what way(s) is(are) the structure of water similar to that of CHCl3? In what way is the structure of water different from tha

Lapatulllka [165]

Answer:

See explanation below

Explanation:

In both cases the central atoms, C in CHCl₃ and O in H₂O, are sp³ hybridized .

Since they are sp³ hybridized we predict an angle between the H-C-Cl and H-O-H of 109.5 º ( tetrahedral ), but two of the sp³ orbitals in water are occupied by lone pairs.

These lone pairs do excercise more repulsion ( need more room ) than the bonds oxygen is making with hydrogen.

As a consequence of this repulsion the angles H-O-H are less than the predicted 109.5º in tetrahedra. ( Actually is 104.5 º)

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3 years ago