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neonofarm [45]
3 years ago
7

How many times more massive is an oxygen atom than a hydrogen atom?

Chemistry
2 answers:
Nesterboy [21]3 years ago
7 0
Oxygen is 16 times more massive.
Hydrogens atomic mass = 1.001 g/mol
Oxygen atomic mass = 15.999 g/mol
Gala2k [10]3 years ago
3 0
An oxygen atom is 16x more massive than a hydrogen atom.

You can figure this out by comparing the atomic masses of the two elements: oxygen has an atomic mass number of 16, and hydrogen has an atomic mass number of 1. Thus, an oxygen atom is 16 times more massive than a hydrogen atom.
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Determine the mass in grams of 3.75 x 10^21 atoms of zinc. (the mass of one mole of zinc is 65.39 g)
Nastasia [14]

Answer: The mass in 3.75 \times 10^{21} atoms of zinc is 0.405 g.

Explanation:

Given: Atoms of zinc = 3.75 \times 10^{21}

It is known that 1 mole of every substance contains 6.022 \times 10^{23} atoms. So, the number of moles in given number of atoms is as follows.

Moles = \frac{3.75 \times 10^{21}}{6.022 \times 10^{23}}\\= 0.622 \times 10^{-2}\\= 0.0062 mol

As moles is the mass of a substance divided by its molar mass. So, mass of zinc (molar mass = 65.39 g/mol) is calculated as follows.

Moles = \frac{mass}{molar mass}\\0.0062 mol = \frac{mass}{65.39 g}\\mass = 0.405 g

Thus, we can conclude that the mass in 3.75 \times 10^{21} atoms of zinc is 0.405 g.

6 0
3 years ago
Write the formula for the complex ion formed by the metal ion Cr3+ and six NO2- ions as ligands. Decide whether the complex coul
Dmitrij [34]

Answer:The metal complex formed would have the following formula [Cr(NO₂)₆]³⁻. The complex has a net negative charge and hence it can only be isolated as a salt with a positive cation so the formed complex could be isolated as potassium salt. The formula for salt would be K₃[Cr(NO₂)₆].

Explanation:

The metal ion given to us is Cr³⁺ (Chromium) in +3 oxidation state.

The electronic configuration for the metal ion is  [Ar]3d³ so there are vacant 3d metal orbitals  which are available and hence 6 NO₂⁻ ligands can easily attack the metal center and form a metal complex.

The charge on the overall complex can be calculated using the oxidation states of metal and ligand which is provided.  

The (chromium ) Cr³⁺ metal has +3 charge and 6 NO₂⁻ (nitro) ligands have -6 charge and since  the ligands will be  providing a total of 6 - (negative) charge  and hence only 3- (negative ) charge can be neutralized so a net 3- negative charge would be present on the overall complex which is basically present at the metal center :

charge on the complex=+3-6=-3

Let X be the Oxidation state of Cr in complex =[Cr(NO₂)₆]³⁻

                                                          X-6=-3

                                                           X=-3+6

                                                            X=+3

so our calculated oxidation state of Cr is +3 which matches with the provided in question.

As we can see that the overall metal complex has a net negative charge and hence and only positively charged  cations can form a salt with this metal complex and hence only potassium K⁺ ions can form salt with the metal complex.

since overall charge present on the metal complex is -3 so 3 K⁺ ion would be needed to neutralize it and hence the formula of the metal salt would be K₃[Cr(NO₂)₆].

3 0
3 years ago
Which of the following elements has two valence electrons? <br> a. Sr <br> b. Na<br> c. Al<br> d. B
KengaRu [80]
(A sr) should be the answer

8 0
3 years ago
Read 2 more answers
Enter the chemical equation 2h (aq) s2−(aq)→h2s(g).
horrorfan [7]
I don't understand what is (g).
Maybe the answer is 2H<span>(aq)S</span>₂<span>−2(aq) </span>⇒ <span>H</span>₂<span>S</span>₂.
5 0
4 years ago
Backpackers often use canisters of white gas to fuel a cooking stove’s burner. If one canister contains 1.45 L of white gas, and
rusak2 [61]
1 L ------- 1000 cm³
1.45 L ----- ???

1.45 * 1000 = 1450 cm³  ( volume ) 

Density = 0.710 g/cm³

mass =  in Kg 

m = D * V

m = 0.710  * 1450

m = 1029.5 g

1 Kg ------- 1000 g
   kg -------- 1029.5 g

mass = 1029.5 / 1000

mass = 1.0295 Kg

hope this helps!

7 0
3 years ago
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