Answer is: mass of slaked lime is 6.92 grams.
Balanced chemical reaction: Ca(OH)₂ + 2NH₄Cl → CaCl₂ + 2NH₃ + 2H₂O.
m(NH₄Cl) = 10 g; mass of ammonium chloride.
M(NH₄Cl) = 14 + 1·4 + 35.5 · g/mol.
M(NH₄Cl) = 53.5 g/mol; molar mass of ammonium chloride.
n(NH₄Cl) = m(NH₄Cl) ÷M(NH₄Cl).
n(NH₄Cl) = 10 g ÷ 53.5 g/mol.
n(NH₄Cl) = 0.187 mol; amount of ammonium chloride.
From balanced chemical reaction: n(NH₄Cl) : n(Ca(OH)₂) = 2 : 1.
n(Ca(OH)₂) = 0.093 mol.
m(Ca(OH)₂) = n(Ca(OH)₂) · M(Ca(OH)₂).
m(Ca(OH)₂) = 0.093 mol · 74.1 g/mol.
m(Ca(OH)₂) = 6.92 g.
A. most science uses inductive reasoning
By definition titraion of a monoprotic acid with means that the equivalence point implies netrality of the solution, which is pH = 7.
So, the answer is that pH will be equal to 7 at the equivalence.
Given that the acid is monoprotic and KOH has one OH- radical per molecule of KOH, the titration will require the same number of moles of acid than base to reach the equivalence point, as you can see in this equation, representing the monoprotic acid as HA:
HA + KOH = K(+) + A(-) + H2O => 1 mol HA per 1 mol KOH.
Answer:
C would be the right answer
