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zhuklara [117]
3 years ago
8

Examine the chemical reaction and lab scenario.

Chemistry
1 answer:
Ierofanga [76]3 years ago
3 0

Explanation:

Percentage Yield

= (3.37g/3.81g) * 100% = 88.45%.

Therefore 88.45% SO2 is the percentage yield.

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HELP FOR MY FINAL PLEASE PLEASE
In-s [12.5K]

For average speed, we divide the total distance covered by the total time taken.

After doing that, you will see that Jane has the lowest average speed.

7 0
2 years ago
__________ could be the formula of an alkene. a. c3h8 b. c2h8 c. c6h6 d. c3h6 e. c17h36
drek231 [11]

The general formula for alkenes is CnH2n, the formula with hydrogen count double the carbon count should be the correct formula for alkene and that is d. C3H6.

What are alkenes?

Alkenes, commonly known as olefins, are organic unsaturated hydrocarbons that have one or more carbon-carbon double bonds in their chemical structure and are composed of carbon and hydrogen atoms.

Alkenes are unsaturated hydrocarbons with a double bond between the carbon atoms. Carbon atoms are connected by at least one double bond. The general formula for alkenes is C n H 2n. Olefin is frequently substituted with alkenes. The word "olefin" comes from the Greek phrase "olefin gas," which denotes the production of oil.

<u>Since, their general formula is CnH2n, the formula with hydrogen count double the carbon count should be the correct formula for alkene and that is d. C3H6.</u>

To learn more about alkenes from the given link below,

brainly.com/question/27179090

#SPJ4

6 0
1 year ago
A balloon occupies 1.50 L with 0.205 mol of carbon dioxide. How many moles would be required to increase the size of the balloon
Gekata [30.6K]

Answer:

0.683 moles of the gas are required

Explanation:

Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:

V₁n₂ = V₂n₁

<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>

<em />

Computing the values of the problem:

1.50Ln₂ = 5L*0.205mol

n₂ = 0.683 moles of the gas are required

<em />

8 0
3 years ago
Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur
Alenkinab [10]

Answer:

\large \boxed{\text{-10.0 kJ}}

Explanation:

1. Calculate the work

w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm

2. Convert litre-atmospheres to joules

w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}

The negative sign indicates that the work was done against the surroundings.

4 0
3 years ago
How many moles are in 5.96g of MgCO,?
nikdorinn [45]

Answer:

201.1046

hope that helped :)

6 0
3 years ago
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