After 16.5 s, a jogger’s displacement is 200.0 m. What is her average velocity in m/s? In km/h?

A 0.4-kg toy train car moving forward at 3 m/s collides with and sticks to a 0.8–kg toy car that is traveling in the opposite di

Gemiola [76]

Hey there!

Seems like you're looking for the size and direction to the final velocity of the two cars. To find it, you must solve it like this.

0.4 kg(3 m/s) + 0.8kg(–2 m/s) = 1.2 kg m/s -1.6 kg m/s = –0.4 kg m/s

–0.4 kg m/s = 1.2 kg(v) = (–0.4 kg m/s)/(1.2 kg) = v = –0.33 m/s

So, the cars are traveling at -0.33 m/s in the direction of the second car.

Hope this helps

<em>Tobey</em>

4 0

3 years ago

2 ways in which a weather satellite can orbit the earth

avanturin [10]

Answer:

The two most common types of orbit are "geostationary" and "polar."

6 0

2 years ago

Read 2 more answers

The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second if i

Sergio [31]

Answer with Explanation:

We are given that

Diameter of fighter plane=2.3 m

Radius= $r=\frac{d}{2}=\frac{2.3}{2}=1.15 m$

a.We have to find the angular velocity in radians per second if it spins=1200 rev/min

Frequency= $\frac{1200}{60}=20 Hz$

1 minute=60 seconds

Angular velocity= $\omega=2\pi f$

Angular velocity= $2\times \frac{22}{7}\times 20=125.7 rad/s$

b.We have to find the linear speed of its tip at this angular velocity if the plane is stationary on the tarmac.

$v=r\omega=1.15\times 125.7=144.56 m/s$

c.Centripetal acceleration= $\omega^2 r=(125.7)^2(1.15)=18170.56 m/s^2$

Centripetal acceleration== $\frac{18170.56\times g}{9.81}=1852.25 g m/s^2$

7 0

3 years ago

Mila both 2 kg of cheese in the market to be used for her Mac and cheese recipe. How many pounds does a 2.00 kg of cheese weigh?

gogolik [260]

Answer:

The answer is 4 pounds

Explanation:

The explanation is that 1 kilogram is equal to 2 pounds so multiply the kilogram with the 1 pound

8 0

3 years ago

A spacecraft and a staellite are at diametrically opposite position in the same circular orbit of altitude 500 km above the eart

Tanya [424]

Answer:

Hello the diagram related to your question is attached below

answer: a) 851 m/s

b) 8506.1 secs

Explanation:

calculate the periodic time of the satellite using the equation below

t = $\frac{2\pi }{R} \sqrt{\frac{(R+h)^{3} }{g} }$ -- ( 1 )

where ; R = 6370 km

h = 500 km

g = 9.81 m/s^2

input given values into equation 1

t = 5670.75 secs

next calculate the periodic time taken by the space craft

<u>a) determine the increase in speed </u>

V = v - $\sqrt{\frac{gR^2}{R + h} }$

where ; v = 8463 m/s , R = 6370 km, h = 500 km

V = 851 m/s

b) Determine the periodic time for the elliptic orbit

τ = $\frac{3t}{2}$

= $\frac{3*5670.76}{2}$ = 8506.1 secs

attached below is the remaining part of the detailed solution

5 0

3 years ago