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damaskus [11]
3 years ago
5

A worker is pushing a crate of tools up a ramp into a truck. The crate has a mass of 120 kg and is accelerating at a rate of 1.0

5 m/s^2. Once he finishes pushing that crate up, he then takes another crate that is 3 times as massive and pushes it up the ramp with an acceleration of 0.71 m/s^2. What is the ratio of the force the worker used on the on the 120 kg crate and the more massive crate? a. 0.218 b. 0.493 c. 1.68 d. 1.07
Physics
1 answer:
Andrej [43]3 years ago
7 0

Answer:

b. 0.493

Explanation:

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OLga [1]

Answer: 2.83 J/mol

Explanation:

Heat of solution, sometimes interchangeably called enthalpy of solution, is said to be the energy released or absorbed when the solute dissolves in the solvent. A solute is that which can dissolve in a solvent, to form a solution

Given

No of moles of CaCl = 7.5 mol

Total energy used = 21.2 J

Heat of solution = q/n where

q = total energy

n = number of moles

Heat of solution = 21.2 / 7.5

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8 0
3 years ago
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During fabrication processes, polymeric materials are generally subjected to which of the following conditions? The ambient temp
geniusboy [140]

Answer:

- Elevated temperatures.

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Explanation:

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High pressures and temperatures are necessary, but parts of good finish and at high production speeds are obtained

3 0
3 years ago
How do scientists use inference?
alexgriva [62]
Their inferences are based on evidence that they collect during their investigations. Readers learn that scientists gather and interpret evidence and draw conclusions based on this evidence. ... Once scientists have gathered evidence, they use it to make inferences about the things they are investigating.
5 0
3 years ago
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-Dominant- [34]

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5 0
3 years ago
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The efficiency of a device such as a lamp can be calculated using this equation:
loris [4]

efficiency = (useful energy transferred ÷ energy supplied) × 100

It's easy to use this formula, but we have to know both the useful energy and the energy supplied.  The drawing doesn't tell us the useful energy, so we have to find a clever way to figure it out.  I see two ways to do it:

<u>Way #1:</u>

We all know about the law of conservation of energy.  So we know that the total energy coming out must be  250J, because that's how much energy is going in.  The wasted energy is 75J, so the rest of the 250J must be the useful energy . . . (250J - 75J) = 175J useful energy.

(useful energy) / (energy supplied) =  (175J) / (250J) = <em>70% efficiency</em>

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<u>Way #2: </u>

How much of the energy is wasted ? . . . 75J wasted

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30% of the input energy is wasted.  That leaves the other <em>70%</em> to be useful energy.

6 0
3 years ago
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