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Mazyrski [523]
3 years ago
5

Among the elements listed, which would show the largest increase between the second and third ionization energies and why?

Chemistry
1 answer:
Yuri [45]3 years ago
4 0
Ionization energy increases from left to right in the row and from bottom to top in a column. Also as we get closer to the nucleus it would be harder to take electrons out. B  (atomic #5) has 2 layers of electron 2 and 3 atom in each layer. P has 15 so it would be 2,8 and 5 respectively. Ca is 20 so 2,8,8,2 and Zn is 30 and it would be 2,18,8,2.
For energy between second and third ionization we are looking at taking out the 3rd electron. B already has 3 electron in the first layer so its easy to take them all. P has 5 in the last layer so again easy. But when we look at Ca and Zn after the 2nd electron (in the last layer) we should change the layer go one layer inside. So this needs more energy. To pick between Zn and Ca (they are in the same row)  I mentioned earlier that in one row as we go to the right ionization energy increases so the answer is Zn. 
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What is the main difference in covalent bonds in diatomic chlorine and diatomic oxygen? diatomic means two atoms of the same typ
Aneli [31]
The correct response is C. Chlorine forms 1 covalent bond while Oxygen forms 2 covalent bonds.
3 0
3 years ago
To determine the concentration of a sample of calcium hydroxide, 1.45M HCl is added drop-wise using a burst. Write the balanced
GenaCL600 [577]

Answer:

H^+(aq) + OH^-(aq) —> H2O(l)

Explanation:

We'll begin by writing the balanced equation for the reaction.

2HCl(aq) + Ca(OH)2(aq) —> CaCl2(aq) + 2H2O(l)

Ca(OH)2 is a strong base and will dissociates as follow:

Ca(OH)2(aq) —> Ca^2+(aq) + 2OH^-(aq)

HCl is a strong acid and will dissociates as follow:

HCl(aq) —> H^+(aq) + Cl^-(aq)

Thus, In solution a double displacement reaction occurs as shown below:

2H^+(aq) + 2Cl^-(aq) + Ca^2+(aq) + 2OH^-(aq) —> Ca^2+(aq) + 2Cl^-(aq) + 2H2O(l)

To get the net ionic equation, cancel out Ca^2+ and 2Cl^-

2H^+(aq) + 2OH^-(aq) —> 2H2O(l)

H^+(aq) + OH^-(aq) —> H2O(l)

7 0
3 years ago
Which product is used on the natural nail prior to product application to assist in adhesion and serves to chemically bond the e
ira [324]

The product that is used on the natural nail prior to application to assist in adhesion and serves to chemically bond the enhancement product to the natural nail is known as nail primer.

<h3>What is a nail primer?</h3>

A nail primer is a chemical agent used in esthetic centers before applying a colored polish to the nails and serves as an adhesive product.

The nail primers are also very useful for improving the cleaning efficiency of the product before its application.

Nail care products include different types of chemical formulations such as, for example, creams that reinvigorate the cuticle.

In conclusion, the chemical formulation employed on the natural nail that is capable of enhancing and also assisting adhesion is called the nail primer.

Learn more about nail esthetic products here:

brainly.com/question/14498053

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8 0
2 years ago
H. Nitrogen gas and hydrogen gas combine to produce ammonia gas (NH3).
DedPeter [7]

Answer:

<u>27.3 L</u>

Explanation:

<u>Reaction</u>

  • N₂ (g) + 3H₂ (g) ⇒ 2NH₃ (g)
  • This is the basic reaction at STP

<u>Solving</u>

  • 10 g N₂ x 1 mol NH₃/28 g N₂ x 3 mol H₂/1 mole N₂
  • ⇒ 1.07 mol H₂

  • V = nRT/P [From Ideal Gas Equation]
  • V = 1.07 x 62.36 x 298 K / 735
  • V = <u>27.3 L</u>
4 0
2 years ago
What is the density of lead (in g/cm^3 3 ) if a rectangular bar measuring 0.500 cm in height, 1.55 cm in width, and 25.00 cm in
Viktor [21]

Answer:

Density = 11.4 g/cm³

Explanation:

Given data:

Density of lead = ?

Height of lead bar = 0.500 cm

Width of lead bar = 1.55 cm

Length of lead bar = 25.00 cm

Mass of lead bar = 220.9 g

Solution:

Density = mass/ volume

Volume of bar = length × width × height

Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm

Volume of bar = 19.4 cm³

Density of bar:

Density = 220.9 g/ 19.4 cm³

Density = 11.4 g/cm³

3 0
3 years ago
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