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2 years ago

5

Part A: Find the GCF of 56 and 96. It is 8, already did this

1 answer:

enot [183]2 years ago

3 0

Question: Part A: Find the GCF of 56 and 96. It is 8, already did this

Part B: Using the GCF you found in Part A, rewrite 56 + 96 as two factors. One factor is the GCF and the other is the sum of two numbers that do not have a common factor. Show your work.

Answer & explanation: Quick-Start Guide. When you enter an expression into the calculator, the calculator will simplify the expression by expanding multiplication and combining like terms. This website will help you out, I think! https://wpblog.wyzant.com lessons Expression Factoring Calculator – Wyzant Lessons

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A line segment has endpoints Q(-16, -12) and R(21, -8).

gulaghasi [49]

Answer:

(2.5, - 10 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

here (x₁, y₁ ) = (- 16, - 12 ) and (x₂, y₂ ) = (21, - 8 ) , then

midpoint = ( $\frac{-16+21}{2}$ , $\frac{-12-8}{2}$ ) = ( $\frac{5}{2}$ , $\frac{-20}{2}$ ) = (2.5, - 10 )

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2 years ago

Amarosa runs 3/4 mile everyday. How many miles does she run in 5 days?

Andre45 [30]

Answer:

3.75 or 3 3/4

Step-by-step explanation:

(3/4) times 5 equals 3.75

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3 years ago

Is the ratio 375 miles to 15 gallons a rate? Explain.

vodka [1.7K]

Answer:

It's not correct

Because

Ratio is the comparison of two quantities having same units

So this ratio can't be taken

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3 years ago

Can someone please help me with math.

notsponge [240]

Answer:

your answer is line plot D.

Step-by-step explanation:

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2 years ago

100 points!! <br> Please solve question 50 in detail

SCORPION-xisa [38]

Answer:

2.62

Step-by-step explanation:

$log_{b} \frac{b^{2}x^{\frac{5}{2} }}{\sqrt{y}}$

First, write the square root as exponent.

$log_{b} \frac{b^{2}x^{\frac{5}{2} }}{y^{\frac{1}{2}}}$

Move the denominator to the numerator and negate the exponent.

$log_{b}(b^{2}x^{\frac{5}{2}}y^{-\frac{1}{2}})$

Use log product property.

$log_{b}(b^{2}) + log_{b}(x^{\frac{5}{2}}) + log_{b}(y^{-\frac{1}{2}})$

Use log exponent property.

$2 log_{b}(b) + {\frac{5}{2}}log_{b}(x) - {\frac{1}{2}}log_{b}(y)$

Substitute values.

$2(1) + \frac{5}{2}(0.36) - \frac{1}{2}(0.56) \\2.62$

4 0

3 years ago

Read 2 more answers