Part A: Find the GCF of 56 and 96. It is 8, already did this

Mathematics

1 answer:

enot [183]2 years ago

3 0

Question: Part A: Find the GCF of 56 and 96. It is 8, already did this

Part B: Using the GCF you found in Part A, rewrite 56 + 96 as two factors. One factor is the GCF and the other is the sum of two numbers that do not have a common factor. Show your work.

Answer & explanation: Quick-Start Guide. When you enter an expression into the calculator, the calculator will simplify the expression by expanding multiplication and combining like terms. This website will help you out, I think! https://wpblog.wyzant.com lessons Expression Factoring Calculator – Wyzant Lessons

You might be interested in

How to simplify -3(x+4)-(x-3)

aev [14]

Step-by-step explanation:

$-3(x+4)-(x-3) \\ - 3x - 12 - x - 3 \\ - 4x - 15 \\ - 4x = 15 \\ x = - \frac{15}{4}$

4 0

3 years ago

I'LL GIVE BRAINLIEST !!! FASTER<br><br>please explain how do you get the answer

lyudmila [28]

Answer:

84°

Step-by-step explanation:

angles in a quadrilateral add to 360°. 360-(114+76)=5x =170°. 170°/5 = 32°. x=32°

angles on a straight line add to 180°.

2x = 64°. 180-64=116°. y=116°.

y-x = 116-32 = 84°

7 0

2 years ago

Read 2 more answers

PLEASE HELP ME!! AT LEAST DO 2 PROBLEMS!

damaskus [11]

1. 4n/5 = 4000 miles. n = 5000.
2. I can't read the whole thing.
3. 3000 miles.
4. Can't read the whole thing.

Hope I kinda helped.

4 0

3 years ago

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil

Furkat [3]

Answer:

t = 5.25 seconds

Step-by-step explanation:

Given that,

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation:

$h(t)=-16t^2+48t+190$

It is assumed to find the time when the projectile will hit the ground. When the projectile hit the ground, its height is equal to 0 such that,

$-16t^2+48t+190=0$

It forms a quadratic equation such that,

$t=\dfrac{-b+\sqrt{b^{2}-4ac } }{2a},\dfrac{-b-\sqrt{b^{2}-4ac } }{2a}\\\\t=\dfrac{-48+\sqrt{(48)^{2}-4\times (-16)(190) } }{2\times (-16)},\dfrac{-48-\sqrt{(48)^{2}-4\times (-16)(190) } }{2\times (-16)}\\\\t=-2.25, 5.25$