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bazaltina [42]
3 years ago
8

I need help with number 5 and 7

Chemistry
1 answer:
beks73 [17]3 years ago
3 0

Answer: question 5 would be: Ww,  Question 7 would be 0/100

Explanation: question 5, I know is right, but I can't really see what question 7 says at the end, from what I can see there is a 0% probability of it being ff for a genotype.     Hope this helps.

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When does the dipole arrow point to Atom A? (Use electronegativity in your explanation)
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Answer:

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8 0
3 years ago
??????????????????<br> Why are quantities important in the study of chemistry give an example please
slamgirl [31]

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Explanation:

8 0
3 years ago
How many moles of water molecules are found in 3.80 moles of zinc(ii) sulfate heptahydrate?
Sindrei [870]
Zinc (ii) sulfate heptahydrate has a formula of ZnSO4.7H2O 
Therefore, note that one mole of ZnSO4.7H2O, contains 7 moles of H2O,
Hence, 3.8 moles of ZnSO4.7H2O will contain;
   3.8 × 7/1
  = 26.6 moles of H2O
3 0
4 years ago
Please use the below balanced equation to answer this question.    2H2(g)  +  O2(g)  -&gt;   2H2O(l) How many grams of water wil
Blizzard [7]
At STP (standard temperature and pressure conditions), 1 mol of any gas occupies 22.4 L 
This rule is applied to O₂
22.4 L volume occupied by 1 mol
Therefore 83.4 L occupied by - 1/ 22.4 x 83.4 = 3.72 mol
stoichiometry of O₂ to H₂O is 1:2
then the number of moles of water produced - 3.72 mol x 2= 7.44 mol
mass of water produced - 7.44 mol x 18.01 g/mol = 134.1 g
correct answer is D

4 0
3 years ago
Consider the weak acid ch3cooh (acetic acid). if a 0.048 m ch3cooh solution is 5.2% ionized, determine the [h3o+] concentration
Tatiana [17]
To determine the equilibrium concentration of hydronium ions in the solution, we use the given value of the percent ionized. Percent ionized is the percent of the ions that is dissociated into the solution. It is equal to the concentration of an ionized species over the initial concentration of the compound multiplied by 100 percent. For this case, the dissociation of the weak acid has a 1 is to 1 ratio to the ionized species such that the concentration of the CH3COO- and H+ ions at equilibrium would be equal. We calculate as follows:

5.2% = 5.2 M H3O+ / 100 M CH3COOH
5.2 M H3O+ / 100 M CH3COOH = [H3O+] / 0.048 M CH3COOH
[H3O+] = 0.2496 M 
3 0
3 years ago
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