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zimovet [89]
3 years ago
14

What is the Bronsted acid of H2PO4- + OH-. ---- HPO42- + H2O?​

Chemistry
2 answers:
RoseWind [281]3 years ago
7 0

Answer:

The bronsted- Lowry acid is H₂PO₄⁻

Explanation:

Bronsted-Lowry acid  donates a proton (H⁺)

H₂PO₄⁻ + OH⁻ → HPO₄²⁻ + H₂O

In the reaction above, H₂PO₄⁻ is donating the proton to OH⁻ resulting in H₂O and the deprotonated species. This makes it a bronsted-Lowry acid.

STALIN [3.7K]3 years ago
4 0

<u>Answer:</u>

<em>H_2 PO_4^- is the Bronsted acid.</em>

<em></em>

<u>Explanation:</u>

An acid is a substance that can donate  one or more proton  

A base is a substance which can accept one or more protons

(Bronsted Acid)    +   (Bronsted Base) ---->  Conjugate Base + Conjugate acid                            

H_2 PO_4^-  + OH^-< -------- > HPO_4^{-2}  + H_2 O

Here we see  

H_2 PO_4^-  donates or loses H^+ ion to form HPO_4^{-2}. Hence H_2 PO_4^- is the Bronsted acid (Answer)

Acid loses H+ (proton) to  forms conjugate Base (HPO_4^{-2})

OH^- is the bronsted Base since it gains or accepts H^+ ion to form H_2 O

Base gains H+ (proton) to forms conjugate Acid (H_2 O)

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<u>Answer:</u> The final concentration of potassium nitrate is 5.70\times 10^{-6}M

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M_2\text{ and }V_2 are the molarity and volume of the concentrated KNO_3 solution

M_3\text{ and }V_3 are the molarity and volume of diluted KNO_3 solution

We are given:

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1.424\times 10^{-4}\times 10=M_3\times 250\\\\M_3=\frac{1.424\times 10^{-4}\times 10}{250}=5.70\times 10^{-6}M

Hence, the final concentration of potassium nitrate is 5.70\times 10^{-6}M

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