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nika2105 [10]
2 years ago
8

\mathrm{question \hookleftarrow}}" alt=" \huge{ \mathrm{question \hookleftarrow}}" align="absmiddle" class="latex-formula">
Calculate equivalent resistance of two resistors R1 and R2 in parallel where,

\sf  R_ 1  = (6 \pm0.2 )\:  \: ohms
\sf  R_ 2  = (3 \pm0.1 )\:  \: ohms
​
Physics
2 answers:
gulaghasi [49]2 years ago
7 0

Answer:

Let R is the equivalent resistance for parallel combination and ΔR is the error(in its measurement respective to the error in the values of resistors)

Hence,

R/1 =1/R¹ + 1/R

R/1 = R¹+R²/R¹+ R²

R= 3+6/3×6

∴R=2Ω

Now,

Δ R /R²=ΔR¹/ (R 1 )²+ΔR²+ (R2)²

ΔR /R²=0.1/(3) +0.5(6)²

ΔR = 4

0.1ΔR=0.1

Hence the resistance of the combination is

R=(2.00±0.1)Ω

lakkis [162]2 years ago
5 0

Answer:

<em>For a parallel circuit with two resistors, the total resistance is calculated from the expression:</em>

<em>For a parallel circuit with two resistors, the total resistance is calculated from the expression:1/R=1/R1+1/R2</em>

<em>For a parallel circuit with two resistors, the total resistance is calculated from the expression:1/R=1/R1+1/R2We are given the total resistance, R, which is 20 ohms and R2 which is 75 ohms. We calculate R1 as follows:</em>

<em>For a parallel circuit with two resistors, the total resistance is calculated from the expression:1/R=1/R1+1/R2We are given the total resistance, R, which is 20 ohms and R2 which is 75 ohms. We calculate R1 as follows:1/20 = 1/R1+1/75 1/R1 : = </em><em><u>11/300 R1 = 27.27 ohms</u></em>

Explanation:

<em>I </em><em>think</em><em> </em><em>this</em><em> is</em><em> your</em><em> answer</em><em> </em><em>hope</em><em> it</em><em> will</em><em> help</em><em> you</em><em> have</em><em> a</em><em> great</em><em> day</em><em> bye</em><em> </em><em>:</em><em>)</em>

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