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3 years ago

An object is propelled along a straight-line path by a force. If the new force were doubled, is acceleration would

Physics

2 answers:

alexandr1967 [171]3 years ago

8 0

The speed would go up
hope it helped!

Aneli [31]3 years ago

6 0

Still go straight but would obviously go up in speed!!

Hope this helps plz mark as brainlist and 5 star

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A rectangular block of steel measures 4cm*2cm*1.5cm*. its mass is 93.6g

nata0808 [166]

Answer:

Explanation:

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3 years ago

Differentiate between earthworm and housefly

mash [69]

Answer:

Earthworm lives in the soil, eats the soil which has organic matter such as decaying vegetation or leaves and crawls. While housefly lives in dirty places, feeds on faeces and flies.

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4 years ago

The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p

beks73 [17]

Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

$v(t)=ate^{-6t}$ (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

$\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]$ (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

$a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}$

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

$v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a$

hence, the maximum speed is v_max = ((1/6)e^-1)a

5 0

3 years ago

A 2-kg toy car accelerates from 5 to 10 m/s.

andre [41]

<h3><u>Full Question:</u></h3>

A 2-kg toy car accelerates from 5 to 10 m/s in 2 seconds. Find the applied force.

<h2><u>Answer:</u></h2>

Force applied is $5\frac {kgm} {s^2}$ .

<h3><u>Explanation:</u></h3>

Force is defined as something which changes or tends to change the velocity of a body. And acceleration is defined as the rate of change of velocity of a body per time. Both of them are vector quantities.

The initial velocity of the body = 5 m/s.

The final velocity of the body = 10 m/s.

So the change in velocity = 10 - 5 m/s = 5m/s.

Time period = 2 seconds.

So acceleration = $\frac52 m/s^2$ = $2.5 m/s^2$