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3 years ago

An object is propelled along a straight-line path by a force. If the new force were doubled, is acceleration would

Physics

2 answers:

alexandr1967 [171]3 years ago

8 0

The speed would go up
hope it helped!

Aneli [31]3 years ago

6 0

Still go straight but would obviously go up in speed!!

Hope this helps plz mark as brainlist and 5 star

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Help please an observer at the North Pole sees the moon phase shown below. What Moon phase will be observed approximately one we

ziro4ka [17]

Answer:

it should be a new moon

Explanation:

4 0

3 years ago

A spring with a spring constant of 110n/m is stretched by 12 cm in the positive direction. How much force is applied to the spri

taurus [48]

The force applied on the spring to stretch it is 13.2 N.

Hooke's law is a law of elasticity discovered by the English scientist Robert Hooke in 1660 that states that the displacement or size of a deformation is directly proportional to the deforming force or load for relatively small deformations of an object. When the load is removed under these conditions, the object returns to its original shape and size.

According to Hooke's law, F = k*e

where F is the force on the spring

k is force constant

and e is extension

F = (110)*(0.12)

F = 13.2 N

For more information on Hooke's law, visit :

brainly.com/question/13348278

#SPJ4

7 0

11 months ago

When a 5.0-kilogram cart moving with a speed of 2.8 meters per second on a horizontal surface collides with a 2.0 kilogram cart

mixer [17]

Here in all such collision type question we can use momentum conservation as we can see that there is no external force on this system

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

as we know that

$m_1 = 5 kg$

$m_2 = 2 kg$

$v_{1i} = 2.8 m/s$

$v_{2i} = 0 m/s$

now from above equation we have

$5(2.8) + 2(0) = m_1v+ m_2v$

$14 = (5+ 2) v$

$v = 2 m/s$

so the speed of combined system is 2 m/s

8 0

3 years ago

The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that

pav-90 [236]

Answer:

The permittivity of rubber is $\epsilon = 8.703 *10^{-11}$

Explanation:

From the question we are told that

The magnitude of the point charge is $q_1 = 70 \ nC = 70 *10^{-9} \ C$

The diameter of the rubber shell is $d = 32 \ cm = 0.32 \ m$

The Electric field inside the rubber shell is $E = 2500 \ N/ C$

The radius of the rubber is mathematically evaluated as

$r = \frac{d}{2} = \frac{0.32}{2} = 0.16 \ m$

Generally the electric field for a point is in an insulator(rubber) is mathematically represented as

$E = \frac{Q}{ \epsilon } * \frac{1}{4 * \pi r^2}$

Where $\epsilon$ is the permittivity of rubber

=> $E * \epsilon * 4 * \pi * r^2 = Q$

=> $\epsilon = \frac{Q}{E * 4 * \pi * r^2}$

substituting values

$\epsilon = \frac{70 *10^{-9}}{2500 * 4 * 3.142 * (0.16)^2}$

$\epsilon = 8.703 *10^{-11}$

7 0

3 years ago

How can meteorologists use the jet stream to predict the weather ?

barxatty [35]

<span>Jet streams act as an invisible director of the atmosphere and are largely responsible for changes in the weather across the globe.
Hope this helps</span>

5 0

2 years ago