B
water is a miscible liquid which mean other liquid can dissolve in it.Also aqueous solution can dissolve in it.
Answer:
An explosion of a star= Supernova
The dense remains of a star= Neutron star
A large mass of gas and dust= Nebula
Explanation:
Answer:
50% or 1/2. The result remains unchanged if the husband were to have G6PD.
Explanation:
For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.
Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype 
. A normal man will have the genotype 
. When the 2 marries:
x = 
It thus means that 50% or 1/2 of their sons will be expected to have G6PD.
Now, assuming the husband has G6PD, the mating becomes:
x 
= 
50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.
Answer:
d) A group that does not drink soda (caffeinated or decaffeinated) or other caffeinated beverages for 10 days
Explanation:
In an experiment, two groups exist as follows: experimental group and control group. Experimental group is the group that receives the experimental treatment (independent variable) while the CONTROL GROUP is the group that does not receive the experimental treatment.
In this experiment, the experimental treatment is the CAFFEINATED SODA (contains caffeine). Hence, the appropriate control group for this experiment will be the group that does not drink any soda (whether caffeinated or decaffeinated) or other caffeinated beverages for 10 days.
The A antibodies will produce A antibodies and the B antibodies will produce B antibodies
