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Vlad1618 [11]
3 years ago
6

Which of the following forces can change velocity?

Physics
2 answers:
Arte-miy333 [17]3 years ago
5 0

Answer:

Option A and Option D are correct.

Explanation:

We have the Newton's second law, that is rate of change of momentum is force.

      \frac{dP}{dt}=F\\\\\frac{mv-mu}{dt}=F

So if there is a force  mv - mu ≠ 0

                                 v - u ≠ 0

                                 v ≠ u

                     Final velocity ≠ Initial velocity.

  a) Option A is correct since there is a force

  b) Option B is wrong since total force is zero.

  c) Option C is wrong since total force is zero.

  d) Option D is correct since there is an effective force

Option A and Option D are correct.          

andrezito [222]3 years ago
4 0
Unequal opposite forces.
(They're unbalanced.)
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Estimate the wavelength corresponding to maximum emission from each of the following surfaces: the sun, a tungsten filament at 2
igomit [66]

Answer

Applying Wein's displacement

\lamda_{max}\ T = 2898 \mu_mK

1) for sun T = 5800 K

      \lambda_{max} = \dfrac{2898}{5800}

      \lambda_{max} = 0.5 \mu_m

2) for tungsten T = 2500 K

      \lambda_{max} = \dfrac{2898}{2500}

      \lambda_{max} = 1.16 \mu_m

3) for heated metal T = 1500 K

      \lambda_{max} = \dfrac{2898}{1500}

      \lambda_{max} = 1.93 \mu_m

4) for human skin T = 305 K

      \lambda_{max} = \dfrac{2898}{305}

      \lambda_{max} = 9.50 \mu_m

5)  for cryogenically cooled metal T = 60 K

      \lambda_{max} = \dfrac{2898}{60}

      \lambda_{max} = 48.3 \mu_m

range of different spectrum

UV ----0.01-0.4

visible----0.4-0.7

infrared------0.7-100

for sun T = 5800

λ              0.01           0.4               0.7                 100

λT             58           2320            4060             5.8 x 10⁵

F                0             0.125             0.491                1

fractions

for UV = 0.125  

for visible = 0.441-0.125 = 0.366

for infrared = 1 -0.491 = 0.509  

8 0
3 years ago
Why is it important that radioisotopes used in diagnostic tests have short half-lives? 20 A) These radioisotopes have a greater
LiRa [457]

Answer:

Option B) This minimizes the harmful side effects of the radiations

Explanation:

Half-life is the time taken for the decay of an radio-active atom in which it disintegrates such that it becomes half of its value at the beginning.... The nuclei should be in active mode for a longer duration sufficient for the treatment of the condition but these nuclei should have a sufficient  shorter half life so that they don't get enough time to cause any  damage to the health of the person other than treating the cause.

A shorter half life gives the assurance that the radiation after the treatment will leave the body without getting accumulated and cause harm to the body cells and other organs.

8 0
3 years ago
How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 4.00
klio [65]

Explanation:

Let us assume that the separation of plate be equal to d and the area of plates is 9 \times 10^{-4} m^{2}. As the capacitance of capacitor is given as follows.

            C = \frac{\epsilon_{o}A}{d}

It is known that the dielectric strength of air is as follows.

               E = 3 \times 10^{6} V/m

Expression for maximum potential difference is that the capacitor can with stand is as follows.

                       dV = E × d

And, maximum charge that can be placed on the capacitor is as follows.

               Q = CV

                   = \frac{\epsilon_{o} A}{d} \times E \times d

                   = \epsilon_{o}AE

                   = 8.85 \times 10^{-12} \times 3 \times 10^{6} \times 4 \times 10^{-4}

                   = 1.062 \times 10^{-8} C

or,                = 10.62 nC

Thus, we can conclude that charge on capacitor is 10.62 nC.

5 0
3 years ago
How much force does an 88kg astronaut exert on his chair while accelerating straight up at 10 m/s^2
Fed [463]
Force=mass*acceleration.         So 88kg*10 m/s^2=880 newtons
6 0
3 years ago
What techniques allow us to identify the presence of different elements?
boyakko [2]

Answer:

c

Explanation:

4 0
2 years ago
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