2 years ago

What is the derivative of te^-t/2

2 answers:

5 0

Y = t*e^(-t/2)

y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=

y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]

Liula [17]2 years ago

5 0

Www.derivative-calculator.net/ will help solve it :)

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Evgesh-ka [11]

Answer:

I think the answer to your question is 5/2

Step-by-step explanation:

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2 years ago

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Sunny_sXe [5.5K]

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Step-by-step explanation:

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then the simplification is ...

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Joanna would have spent $8.94 on apples at the farmers market.

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