What is the derivative of te^-t/2
2 answers:
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Using the normal distribution, the area underneath the shaded region <u>between the two z-scores</u> is given by:
C. 0.6766.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
Hence, for this problem, the area is the <u>p-value of z = 0.75 subtracted by the p-value of z = -1.3</u>.
Looking at the z-table, the p-values are given as follows:
- z = 0.75: 0.7734.
- z = -1.3: 0.0968.
Then:
0.7734 - 0.0968 = 0.6766.
Which means that option C is correct.
More can be learned about the normal distribution at brainly.com/question/15181104
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