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Ymorist [56]
2 years ago
5

The table giver you 4 tree's and I forget what the rest said so I am just lazy and took a sreenshot.

Mathematics
1 answer:
ser-zykov [4K]2 years ago
4 0
<h2>Answer:</h2>

The Maple tree.

<h2>Step-by-step explanation:</h2>

The Sycamore is 15 and 2/3 feet tall, which is 15.667 feet.

The Oak is 14 and 3/4 feet tall, which is 14.75 feet.

The Maple is 15 and 3/4 feet tall, which is 15.75 feet.

The Birch is given as 15.72 feet.

Out of these, the tallest is the Maple, which is at 15.75 feet.

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Which graph represents a function?
Temka [501]

Answer:

The last one

Step-by-step explanation:

x can only have one value whereas y can be constants like in last graph

6 0
3 years ago
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East of Star, the railroad tracks intersect highway 23o as shown above. If 1=133 , find 2.
GrogVix [38]
Hi there.

These two angles sum up to be 180 degrees, so they are supplementary angles. Now, since these angles sum up to 180 degrees (to form a straight line), we only have to subtract 133 from 180 to find angle 2's measurement.

180 - 133 = 47

Angle 2's measurement is 47 degrees.

Voila! 

I hope this helps! Have a great day. :)
6 0
3 years ago
Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
3 years ago
Which of these functions is not a linear function? Why?
Nitella [24]

Answer:

f(x)=x3

Step-by-step explanation:

If you meant f(x)=x3 by f(x)=x^3 then that would be a cubic equation and not linear?

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Identify the zeros of the quadratic function.
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Answer:

y = -2 and y = -5 thus: d)

Step-by-step explanation:

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