A swimmer sprints a short distance for competition. The swimmer is not able to take in enough oxygen to make the ATP needed for the sprint. Which of the following processes is most likely going to occur in the swimmer's muscle cells during the competition? (2 points)
A. Aerobic respiration would continue until oxygen is no longer available, leading to cell death.
B. Aerobic respiration will continue to make the same amount of ATP since oxygen is not required.
C. Anaerobic respiration would be used to produce small amounts of ATP in the absence of oxygen.
D. Anaerobic respiration will produce more ATP than the process used in the presence of oxygen.
<u>Answer:</u>
A swimmer sprints a short distance for competition. The swimmer is not able to take in enough oxygen to make the ATP needed for the sprint. Anaerobic respiration would be used to produce small amounts of ATP in the absence of oxygen and it is the process happens in the swimmer's muscle cells during competition.
<u>Explanation:</u>
- A Swimming sprinter will spend his maximum energy while to cover a short distance in his competition. Quickly he will reduce his oxygen level.
- Oxygen will produce an ATP molecule (Adenosine Triphosphate) which is required for a sprinter.
- The ATP molecule will produce energy for the cells. Aerobic respiration takes place only when in the presence of oxygen.
- While swimming they will not get enough oxygen so the Anaerobic respiration takes place to produce ATP molecule.
Answer:
X-linked recessive
Explanation:
Mostly males seem to manifest this trait
Domains are the highest ranking of organisms in taxonomy. They are notably Bacteria, Eukarya, and Archaea
Answer:
Explanation:
<u>Given that:</u>
ΔMNO ≅ ΔPQR
That means
M ↔ P
N ↔ Q
O ↔ R
So,
∠P ≅ ∠M
Given that P = 3x + 20.4 and M = 5x - 19
3x + 20.4 = 5x - 19
Add 19 to both sides
3x + 20.4 + 19 = 5x
3x + 39.4 = 5x
Subtract 3x to both sides
39.4 = 5x - 3x
39.4 = 2x
2x = 39.4
Divide both sides by 2
x = 19.7
<u>Given that:</u>
P = 3x + 20.4
P = 3(19.7) + 20.4 (x = 19.7)
P = 59.1 + 20.4
P = 79.5°
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
