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miskamm [114]
2 years ago
8

Please help me I'm struggling

Mathematics
1 answer:
PtichkaEL [24]2 years ago
7 0
Help you with what. You did not put any question.
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Please answer the question question correctly with factual information for brainliest.
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A

Step-by-step explanation:

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ALGEBRA HELP ASAP
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When x=1/4 x²=1/16 so f(1/4)=y=2 1/16 last answer
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Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt.
Mariulka [41]
This problem requires the use of the chain rule: dy / dt = [dy / dx] * [dx / dt]

y = √x => dy / dx = 1 / (2√x)

<span>(a) Find dy/dt, given x = 16 and dx/dt = 7.

dy/dt = [ 1/(2√x) ]  * 7 = [1/(2*4)] * 7 = 7/8

(b) Find dx/dt, given x = 64 and dy/dt = 8.

dx/dt = [dy/dt] /  [dy/dx] = 8 / [1/(2√64) ] = 128
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2 years ago
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2/7 + 4/7 = 6/7 Can be rewritten as
4/7 + 2/7 = 6/7
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Please HELP!!! I'll mark you Brianliest!!
Volgvan
The answer is  going to be A.
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