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1 year ago

2 to the power of 3+7+6÷2 BDMAS PLEASE HELP GUYS SCHOOL IN 30 MINUTES

Mathematics

1 answer:

chubhunter [2.5K]1 year ago

7 0

Answer:

10.5

Step-by-step explanation:

Break the problem down into small parts:

2 to the power of 3= 8

8+7+6=

15+6=21

21/2

21 divided by 2 is 10.5

Hope this helps!

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Solve the equation. 4(x − 7) − 128 = 9x − 5(x + 6)

vichka [17]

The equation 4(x − 7) − 128 = 9x − 5(x + 6) has no solution

<h3><u>Solution:</u></h3>

Given that 4(x − 7) − 128 = 9x − 5(x + 6)

We have to find the solution for this equation

4(x − 7) − 128 = 9x − 5(x + 6)

Let us use BODMAS rule to perform the sequence of operations

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.

So let us solve for brackets first

4x - 28 - 128 = 9x - 5x - 30

Now let us perform subtraction

4x - 156 = 4x - 30

Now move the terms from R.H.S to L.H.S

4x - 4x = -30 + 156

$0 \neq 126$

Since there is no value of x that will ever make this a true statement, the solution to the equation above is “no solution”

So this equation has no solution

4 0

3 years ago

Help me out pleaseeee ASAP :(

prisoha [69]

Answer:

Your answer is RSP. THE 3RD one

3 0

2 years ago

What is the answer to <br>2x+3=4x+6-(2x+3)

Grace [21]

I am still learning, and am most likely incorrect.

I believe you remove the 3's since their not needed, and do this:

2x = 4x + 6 - (2x)

so then just ignore "x" and do this:

2 = 4 + 6 - 2

2 = 10 - 2

2 = 8

x = 8

7 0

3 years ago

Consider the following quadratic function Part 3 of 6: Find the x-intercepts. Express it in ordered pairs.Part 4 of 6: Find the

maksim [4K]

Answer:

The line of symmetry is x = -3

Explanation:

Given a quadratic function, we know that the graph is a parabola. The general form of a parabola is:

$y=ax^2+bx+c$

The line of symmetry coincides with the x-axis of the vertex. To find the x-coordinate of the vertex, we can use the formula:

$x_v=-\frac{b}{2a}$

In this problem, we have:

$y=-x^2-6x-13$

Then:

a = -1

b = -6

We write now:

$x_v=-\frac{-6}{2(-1)}=-\frac{-6}{-2}=-\frac{6}{2}=-3$

Part 3:

For this part, we need to find the x-intercepts. This is, when y = 0:

$-x^2-6x-13=0$

To solve this, we can use the quadratic formula:

$x_{1,2}=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot(-1)\cdot(-13)}}{2(-1)}$

And solve:

$x_{1,2}=\frac{6\pm\sqrt{36-52}}{-2}$ $x_{1,2}=\frac{-6\pm\sqrt{-16}}{2}$

Since there is no solution to the square root of a negative number, the function does not have any x-intercept. The correct option is ZERO x-intercepts.

Part 4:

To find the y intercept, we need to find the value of y when x = 0: