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Delicious77 [7]

2 years ago

10

Help help math math math

1 answer:

goblinko [34]2 years ago

6 0

It is 11 33/40. 11 being the whole number and 33/40 the fraction

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3 years ago

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Which statement best describes the area of the triangle shown below?

Molodets [167]

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A triangle.

Step-by-step explanation:

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3 years ago

A page was missing from a 72 - page book. When Josh added up the remaining page numbers, the sum was 2521. Which page was missin

morpeh [17]

The numbers 1 to 72 add up to (1+72) x 72/2 = 73 x 36 = 2628
If we take away what Josh got we have 2628 - 2521 = 107
Pages in a book are odd on the first side and even on the second, so pages 11 and 12 are on the same sheet.
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8 0

3 years ago

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vlada-n [284]

Answer:

132, 390, 244, 492

Step-by-step explanation:

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4 0

2 years ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

3 years ago