Answer:
x=-1 and y=-5
Step-by-step explanation:
ሰላም!
Given expressions let them given as two equations
- y=2+7x....... equation (1)
- -2x+6y=-28..... equation (2)
Thus, substitute y=2+7x into equation (2)
simplify it
subtract 12 from both sides
divide both sides by 40
Therefore, as we get the value of x=-1 substitute it to equation (1) and solve for variable y
To be more sure make a cross check on both of the two expressions
Thus,
1) y=2+7x .... substitute y=-5 and x=-1 and check if it is equal
-5=2+7(-1)
-5=2-5
-5=-5
2)-2x+6y=-28... substitute and check
-2(-1)+6(-5)=-28
2-30=-28... (-a)(-b)=ab
-28=-28
Hope it helps!
Answer:
96% percent and fraction is 24/25
Answer:
Step-by-step explanation:
To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:
![A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%261%261%261%5C%5C3%267%26-1%261%5Cend%7Barray%7D%5Cright%5D)
And the vector B is formed with the solution of each equation of the system:![b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3%5C%5C-3%5C%5C6%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called 
.
![A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]](https://tex.z-dn.net/?f=A_%7B2%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%262%262%5C%5C-7%26-3%265%26-8%5C%5C4%266%261%261%5C%5C3%261%26-1%261%5Cend%7Barray%7D%5Cright%5D)
The value of y using Cramer's rule is:
Find the value of the determinant of each matrix, and divide:
Answer:
2x^5log=1/6
Step-by-step explanation:
using the natural log (e), we were able to give the power of 5 to 2x and then take it out from the parantheses
