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disa [49]
3 years ago
9

A figure skater begins spinning counterclockwise at an angular speed of 3.2 π rad/s. During a 4.5 s interval, she slowly pulls h

er arms inward and finally spins at 7.4 π rad/s. What is her average angular acceleration during this time interval? Answer in units of rad/s2.
Physics
1 answer:
avanturin [10]3 years ago
7 0

Answer:

Explanation:

.93 rad per secundo

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Two objects move toward each other because of gravitational attraction. As the objects get closer and closer, the force between
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<span>Two objects move toward each other because of gravitational attraction. As the objects get closer and closer, the force between them increases. </span>
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Read 2 more answers
A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coe
ikadub [295]

Answer:

f_{fr}=1590.85 N

Explanation:

Here the total force at the horizontal components will be equal to the centripetal force on the car. So we will have:

f_{fr}cos(25)+Nsin(25)=m\frac{v^{2}}{r} (1)

  • f(fr) is the friction force
  • N is the normal force

Now, the sum of forces at the vertical direction is equal to 0.

Ncos(25)-mg-f_{fr}sin(25)=0 (2)          

Let's combine (1) and (2) to find f(fr)

f_{fr}=\frac{(mv^{2}/r)-mgtan(25)}{cos(25)+tan(25)sin(25)}

f_{fr}=\frac{(600*30^{2}/120)-600*9.81*tan(25)}{cos(25)+tan(25)sin(25)}  

f_{fr}=1590.85 N

I hope it helps you!

5 0
3 years ago
Imagine that you pushed a box, applying a force of 60 newtons, over a distance of 4 meters. How much would you have done?
grin007 [14]
You would have done 240 joules of work on the box.

Work = (force)  x  (distance)

         =  (60 newtons)  x  (4 meters)

         =         240 joules  . 
5 0
3 years ago
Piston 1 in the figure has a diameter of 1.87 cm. Piston 2 has a diameter of 9.46 cm.
mariarad [96]

Force necessary to support the object on piston 2 is 24× 10⁴ N.

To find the answer, we need to know about the force and pressure on piston 1 and piston 2.

<h3>What's the pressure on piston 2?</h3>
  • The force on piston 2= mass × acceleration due to gravity

= 991 Kg × 9.8 = 9414.5N

  • Mathematically, force= pressure/area
  • Pressure= force × area of piston

= 9414.5N × π(9.46² cm² /4)

= 9414.5N × π(9.46²× 10^(-4)m²/4)

= 66.2 N/m²

<h3>What's the force needed to held the mass on piston 2?</h3>
  • Pressure on piston 2 = pressure on piston 1
  • Force on piston 1= pressure on piston 1/area of piston 1

= 66.2/ π(1.87² cm² /4)

= 66.2/ π(1.87²×10^(-4)m² /4)

= 24× 10⁴ N

Thus, we can conclude that force necessary to support the object on piston 2 is 24× 10⁴ N.

Learn more about the force and pressure here:

brainly.com/question/769876

#SPJ1

8 0
2 years ago
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