<h3>
Answer:</h3>
225 meters
<h3>
Explanation:</h3>
Acceleration is the rate of change in velocity of an object in motion.
In our case we are given;
Acceleration, a = 2.0 m/s²
Time, t = 15 s
We are required to find the length of the slope;
Assuming the student started at rest, then the initial velocity, V₀ is Zero.
<h3>Step 1: Calculate the final velocity, Vf</h3>
Using the equation of linear motion;
Vf = V₀ + at
Therefore;
Vf = 0 + (2 × 15)
= 30 m/s
Thus, the final velocity of the student is 30 m/s
<h3>Step 2: Calculate the length (displacement) of the slope </h3>
Using the other equation of linear motion;
S = 0.5 at + V₀t
We can calculate the length, S of the slope
That is;
S = (0.5 × 2 × 15² ) - (0 × 15)
= 225 m
Therefore, the length of the slope is 225 m
Answer:
The strength of the magnetic field is 3.5 x 10⁻³ T
Explanation:
Given;
magnitude of the magnetic flux , Φ = 5.90 x 10⁻⁵ T·m²
angle of inclination of the field, θ = 42.0°
radius of the circular plate, r = 8.50 cm = 0.085 m
Generally magnetic flux in a uniform magnetic field is given as;
Φ = BACosθ
where;
B is the strength of the magnetic field
A is the area of the circular plate
Area of the circular plate:
A = πr²
A = π (0.085)² = 0.0227 m²
The strength of the magnetic field:
B = Φ / ACosθ
B = ( 5.90 x 10⁻⁵) / ( 0.0227 x Cos42)
B = 3.5 x 10⁻³ T
Therefore, the strength of the magnetic field is 3.5 x 10⁻³ T
Answer:
Kinetic Energy:120 x 15=1800
Explanation:
