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Sholpan [36]
3 years ago
9

A 9.0 volt battery is connected to four resistors in a parallel circuit. The resistors have 7.0 Ω, 5.0 Ω, 4.0 Ω, and 2.0 Ω respe

ctively. What is the total current in the circuit?
Physics
2 answers:
lidiya [134]3 years ago
5 0
Series,effective resistance =R₁+R₂+R₃...
parallel,effective resistance 1/R=1/R₁ +1/R₂ +1/R₃...
 
Here,effective resistance 1/R =1/7 +1/5+ 1/4+1/2  
                                           =1.092
                                       R = 1/1.092 =0.915Ω
voltage V=9 V 
current I=V/R
           
I=9 / 0.915
            =9.83 A
shepuryov [24]3 years ago
4 0
Parallel resistance = <u />\frac{1}{7} + \frac{1}{5} + \frac{1}{4} + \frac{1}{2}
=\frac{140}{153}

now , V= 9V
V = IR
I = \frac{V}{R}
I = \frac{9}{140} x 153
I = 9.835714 A

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