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pashok25 [27]
3 years ago
13

BRO CAN SOMEONE PLEASE HELP ME

Mathematics
2 answers:
Katena32 [7]3 years ago
7 0
Yes the person is right
SSSSS [86.1K]3 years ago
6 0

Answer:

1st is 30 and 16. 2nd is reduction. 3rd is scale factor of 2/3

Step-by-step explanation:

#1 you dilate by a scale factor of 2 so you just multiply all the sides by 2 to get your answer. 15x2=30 and 8x2= 16.

#2 it is a reduction because m', s', and v' are smaller then m, s, and v

#3 the scale factor is 2/3 because you do the image over the pre-image so -2,2 / -3,3 is 2/3 same is 4,2 / 6,3 and 2,-2 / 3, -3

You might be interested in
I need help people what is 215÷ 9
Dominik [7]

215/9 = 23.888

or

23 with a remainder of 8

I hope I helped


6 0
3 years ago
Read 2 more answers
What is the solution to the equation 1/4x-1/8=7/8+1/2x?<br><br> X=-5<br> X=-4<br> X=4
Rama09 [41]

the answer is x=-4 hope it helps

3 0
3 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
4 years ago
3(7x-5)+5=10x-5 Solve for X
Nina [5.8K]
21x -15 + 5 = 10x - 5
21x -5 = 10x
11x = 5
x = 5/11
5 0
3 years ago
Read 2 more answers
The distribution of a sample of the outside diameters of PVC pipes approximates a normal distribution. The mean is 14.0 inches,
lakkis [162]

Answer:

A. 13.9 and 14.1 inches

See explanation below.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the outside diameters of a population, and for this case we know the distribution for X is given by:

X \sim N(14,0.1)  

Where \mu=14 and \sigma=0.1

If we want the middle 68% of the data we need to have on the tails 16% on each one

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.84   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.16 of the area on the left and 0.84 of the area on the right it's z=-0.994. On this case P(Z<-0.994)=0.16 and P(z>-0.994)=0.84

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.994

And if we solve for a we got

a=14 -0.994*0.1=13.9

And since the distribution is symmetrical for the upper limit we can use z = 0.994 and we have:

z=0.994

And if we solve for a we got

a=14 +0.994*0.1=14.1

So the correct answer for this case would be:

A. 13.9 and 14.1 inches

3 0
4 years ago
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