Answer:
1) f=−8/7 2) z=−3/7
Step-by-step explanation:
1)-f+8=-8f
−f+8=−8f
Step 1: Add 8f to both sides.
−f+8+8f=−8f+8f
7f+8=0
Step 2: Subtract 8 from both sides.
7f+8−8=0−8
7f=−8
Step 3: Divide both sides by 7.
7f/7=−8/7
f=-8/7
2) 6z-5=-z-8
6z−5=−z−8
Step 1: Add z to both sides.
6z−5+z=−z−8+z
7z−5=−8
Step 2: Add 5 to both sides.
7z−5+5=−8+5
7z=−3
Step 3: Divide both sides by 7.
7z/7=−3/7
So, bike=b and accessories=a.
b+a=320
Since the bike is worth 7 times more than the accessories, the b would turn into 7a (because 7 times the cost of accessories is the cost of the bike).
The equation would now turn into 7a+a=320.
Solve for a.
7a+a=320
8a=320
a=40
Now that you know the cost of the accessories, you multiply that 40
by 7 to get the cost of the bike.
40(7)
280
The cost of the bike is $280.
The cost of the accessories are/is $40.
Answer:
Step-by-step explanation:
y=kx
4=k(-2)
k=-2
y=-2x
when x=30
y=-2*30=-60
r = √(3V/πh)
multiply both sides by 3 to eliminate the fraction
πr²h = 3V ( divide both sides by πh )
r² = 3V/ πh ( take the square root of both sides )
r = √(3V/πh)
1 dry quart=1.10
1.10 x 4= 4.4
Final answer: B.
