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Murljashka [212]
2 years ago
7

Pls helprepresent on a number line ​

Mathematics
2 answers:
umka21 [38]2 years ago
8 0

Answer:i dont know but hope this helps

Step-by-step explanation:

A straight line is divided into a number of parts with a unit distance between them. By representing a number on a number line, we can easily tell the difference between two numbers and make comparisons between them. It can also be defined as a line on which numbers are marked at a uniform distance.

scoundrel [369]2 years ago
6 0

Answer:

Refer the given attachment

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ziro4ka [17]

Answer:

a) \frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

The Confidence interval is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and the critical values are:

\chi^2_{\alpha/2}=20.09

\chi^2_{1- \alpha/2}=1.65

And replacing into the formula for the interval we got:

\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0
3 years ago
SOMEONE PLEASE HELP ASAP!!!!!
Margaret [11]

Answer:

<em>x = 1</em>

<em>y = 1</em>

Step-by-step explanation:

<u>System of Equations</u>

We are given the system of equations:

2x + y = 3

x = 2y - 1

Substituting x in the first equation:

2(2y - 1) + y = 3

Operating:

4y - 2 + y = 3

5y = 3 + 2

y = 5/5 = 1

y = 1

Since:

x = 2y - 1

Then:

x = 2(1) - 1

x = 1

Solution:

x = 1

y = 1

7 0
3 years ago
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