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kherson [118]
2 years ago
6

A 75-hp motor that has an efficiency of 91.0% is worn-out and is replaced by a motor that has a high efficiency 75-hp motor that

has an efficiency of 95.4%. Determine the reduction in heat gain in the room due to higher efficiency under full-load conditions (load factor
Engineering
1 answer:
damaskus [11]2 years ago
8 0

Answer:

the reduction in the heat gain is 2.8358 kW

Given that;

Shaft outpower of a motor  = 75 hp = ( 75 × 746 ) = 55950 W

Efficiency of motor  = 91.0% = 0.91

High Efficiency of the motor  = 95.4% = 0.954

now, we know that, efficiency of motor is defined as;  =  /

where   is the electric input given to the motor

so

=  /

we substitute

= 55950 W / 0.91

= 61483.5 W

= 61.4835 kW

now, the electric input given to the motor due to increased efficiency will be;

=  /

we substitute

= 55950 W / 0.954

= 58647.79 W

= 58.6477 kW

so the reduction of the heat gain of the room due to higher efficiency will be;

Q =  -

we substitute

Q = 61.4835 kW - 58.6477 kW

Q = 2.8358 kW

Therefore, the reduction in the heat gain is 2.8358 kW

Explanation:  i hope this answer your question if this is wrong or correct please let me know.also no trying to be rude but can you sent me like a thanks?

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Bind hole, 38 diameter, .50 deep
agasfer [191]

Answer:

59.69021

Explanation:

38/.5 x 3.14159

4 0
2 years ago
While playing a game of catch on the quadrangle, you throw a ball at an initial velocity of 17.6 m/s (approximately 39.4 mi/hr),
MAXImum [283]

Answer:

a) The y-component of velocity just before the ball hits the ground is -14.860 meters per second.

b) The ball is in the air during approximately 2.890 seconds.

c) The horizontal distance covered by the ball is 32.695 meters.

d) The magnitude of the velocity of the ball just before it hits the ground is approximately 18.676 meters per second.

e) The angle of the total velocity of the ball just before it hits the ground is approximately 52.717º below the horizontal.

Explanation:

a) The ball experiments a parabolic motion, which is a combination of horizontal motion at constant velocity and vertical motion at constant acceleration. First, we calculate the time taken by the ball to hit the ground:

y = y_{o} + (v_{o}\cdot \sin \theta) \cdot t+\frac{1}{2}\cdot g\cdot t^{2} (1)

Where:

y_{o}, y - Initial and final vertical position, measured in meters.

v_{o} - Initial speed, measured in meters per second.

\theta - Launch angle, measured in sexagesimal degrees.

g - Gravitational acceleration, measured in meters per square second.

t - Time, measured in seconds.

If we know that y_{o} = 2\,m, y = 0\,m, v_{o} = 17.6\,\frac{m}{s}, \theta = 50^{\circ} and g = -9.807\,\frac{m}{s^{2}}, then the time taken by the ball is:

-4.904\cdot t^{2}+13.482\cdot t +2 = 0 (2)

This second order polynomial can be solved by Quadratic Formula:

t_{1} \approx 2.890\,s and t_{2} \approx -0.141\,s

Only the first root offers a solution that is physically reasonable. That is, t \approx 2.890\,s.

The vertical velocity of the ball is calculated by this expression:

v_{y} = v_{o}\cdot \sin \theta +g\cdot t (3)

Where:

v_{o,y}, v_{y} - Initial and final vertical velocity, measured in meters per second.

If we know that v_{o} = 17.6\,\frac{m}{s}, \theta = 50^{\circ}, g = -9.807\,\frac{m}{s^{2}} and t \approx 2.890\,s, then the final vertical velocity is:

v_{y} = -14.860\,\frac{m}{s}

The y-component of velocity just before the ball hits the ground is -14.860 meters per second.

b) From a) we understand that ball is in the air during approximately 2.890 seconds.

c) The horizontal distance covered by the ball (x) is determined by the following expression:

x = (v_{o}\cdot \cos \theta)\cdot t (4)

If we know that v_{o} = 17.6\,\frac{m}{s}, \theta = 50^{\circ} and t \approx 2.890\,s, then the distance covered by the ball is:

x = 32.695\,m

The horizontal distance covered by the ball is 32.695 meters.

d) The magnitude of the velocity of the ball just before hitting the ground (v), measured in meters per second, is determined by the following Pythagorean identity:

v = \sqrt{(v_{o}\cdot \cos \theta )^{2}+v_{y}^{2}} (5)

If we know that v_{o} = 17.6\,\frac{m}{s}, \theta = 50^{\circ} and v_{y} = -14.860\,\frac{m}{s}, then the magnitude of the velocity of the ball is:

v \approx 18.676\,\frac{m}{s}.

The magnitude of the velocity of the ball just before it hits the ground is approximately 18.676 meters per second.

e) The angle of the total velocity of the ball just before it hits the ground is defined by the following trigonometric relationship:

\tan \theta = \frac{v_{y}}{v_{o}\cdot \cos \theta_{o}}

If we know that v_{o} = 17.6\,\frac{m}{s}, \theta_{o} = 50^{\circ} and v_{y} = -14.860\,\frac{m}{s}, the angle of the total velocity of the ball just before hitting the ground is:

\theta \approx -52.717^{\circ}

The angle of the total velocity of the ball just before it hits the ground is approximately 52.717º below the horizontal.

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3 years ago
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Answer:

Explanation:

First of all,we need to know what kind of research and how important it is before determining which computation method to use .

Then compare end result of research and cost of  expensive methods .

Then we should opt for the best expensive method to be used for the given application.

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Technician A says that as long as the dog (clutch) teeth of the synchronizer are rounded, the synchronizer can be reused. Techni
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Neither of the technicians are correct.

<h3>Who is a technician?</h3>

A technician simply means an individual who looks after the technical equipments in a company.

In this case, the teeth of the synchronizer are not rounded, the synchronizer can be reused. This shows that he is incorrect likewise technician B.

Learn more about technicians on:

brainly.com/question/1548867

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what is the largest, low-cost airline carrier in the world, which recently canceled thousands of flights for reasons partially d
IgorC [24]

The largest, low-cost airline carrier in the world that recently canceled thousands of flights for reasons partially disputed by the federal aviation administration (FAA) is Southwest Airlines.

Southwest Airlines canceled 2,500 flights in just a few days.

According to Southwest Airlines, the cause of the cancellation is due to air traffic control problems and disruptive weather.

While FAA claimed that nothing like a reported case of air traffic and staffing shortages.

Southwest Airlines is the world's largest low-cost carrier and has its main office is located in Dallas, Texas.

Hence, in this case, it is concluded that the correct answer is "Southwest Airlines."

Learn more here: brainly.com/question/24782945

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