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tigry1 [53]
2 years ago
13

1)

Engineering
1 answer:
Kryger [21]2 years ago
7 0

Answer:

b

Explanation:

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True

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Complete the following sentence. Engineers explore biology, chemistry, and physics for use in scenarios.
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3 years ago
The current through a 10-mH inductor is 10e−t∕2 A. Find the voltage and the power at t = 8 s.
NNADVOKAT [17]

Answer:

voltage = -0.01116V

power = -0.0249W

Explanation:

The voltage v(t) across an inductor is given by;

v(t) = L\frac{di(t)}{dt}             -----------(i)

Where;

L = inductance of the inductor

i(t) = current through the inductor at a given time

t = time for the flow of current

From the question:

i(t) = 10e^{-t/2}A

L = 10mH = 10 x 10⁻³H

Substitute these values into equation (i) as follows;

v(t) = (10*10^{-3})\frac{d(10e^{-t/2})}{dt}

Solve the differential

v(t) = (10*10^{-3})\frac{-1*10}{2} (e^{-t/2})

v(t) = -0.05 e^{-t/2}

At t = 8s

v(t) = v(8) = -0.05 e^{-8/2}

v(t) = v(8) = -0.05 e^{-4}

v(t) = -0.05 x 0.223

v(t) = -0.01116V

(b) To get the power, we use the following relation:

p(t) = i(t) x v(t)

Power at t = 8

p(8) = i(8) x v(8)

i(8) = i(t = 8) = 10e^{-8/2}

i(8) = 10e^{-4}

i(8) = 10 x 0.223

i(8) = 2.23

Therefore,

p(8) = 2.23 x -0.01116

p(8) = -0.0249W

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3 years ago
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