Answer:
the required diameter of the rod is 9.77 mm
Explanation:
Given:
Length = 1.5 m
Tension(P) = 3 kN = 3 × 10³ N
Maximum allowable stress(S) = 40 MPa = 40 × 10⁶ Pa
E = 70 GPa = 70 × 10⁹ Pa
δ = 1 mm = 1 × 10⁻³ m
The required diameter(d) = ?
a) for stress
The stress equation is given by:
A is the area = πd²/4 = (3.14 × d²)/4
Substituting the values, we get
d = (9.77 × 10⁻³) m
d = 9.77 mm
b) for deformation
δ = (P×L) / (A×E)
A = (P×L) / (E×δ) = (3000 × 1.5) / (1 × 10⁻³ × 70 × 10⁹) = 0.000063
d² = (4 × A) / π = (0.000063 × 4) / 3.14
d² = 0.0000819
d = 9.05 × 10⁻³ m = 9.05 mm
We use the larger value of diameter = 9.77 mm
Answer:
Damping ratio 
Explanation:
Given that
m=4.2 kg,K=85.9 N/m,C=1.3 N.s/m
We need to find damping ratio
We know that critical damping co-efficient
N.s/m
Damping ratio(
) is the ratio of damping co-efficient to the critical damping co-efficient
So 
So damping ratio
Answer:
In this era, Sun Ra was among the first of any musicians to make extensive and pioneering use of synthesizers and other various electronic keyboards; he was given a prototype Minimoog by its inventor, Robert Moog.
Explanation:
Answer:
Highest temperature rise allowable = ΔT = 21.22°C
Highest allowable temperature = ΔT + 20 = 41.22°C
Explanation:
From literature, the coefficient of volume expansion of water between 20°C and 50°C = β = (0.377 × 10⁻³) K⁻¹
Volume expansivity is given by
ΔV = V β ΔT
ΔV = Change in volume
V = initial volume
β = Coefficient of volume expansion = (0.377 × 10⁻³) K⁻¹ = 0.000377 K⁻¹
ΔT = Change in temperature = ?
It is given in the question that maximum volume increase the tank can withstand is
(ΔV/V) × 100% = 0.8%
(ΔV/V) = 0.008
V β ΔT = ΔV
β ΔT = (ΔV/V)
β ΔT = 0.008
ΔT = (0.008/β)
ΔT = (0.008/0.000377)
ΔT = 21.22°C
Highest temperature rise allowable = ΔT = 21.22°C
Highest allowable temperature = ΔT + 20 = 41.22°C
Hope this Helps
Answer:
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