Answer:
1.0MG
Explanation:
to solve this problem we use this formula
S₀-S/t = ksx --- (1)
the values have been given as
concentration = S₀ = 250mg
effluent concentration = S= 10mg
value of K = 0.04L/day
x = 3000 mg
when we put these values into this equation,
250-10/t = 0.04x10x3000
240/t = 1200
we cross multiply from this stage
240 = 1200t
t = 240/1200
t = 0.2
remember the question says that 5MGD is required to be treated
so the volume would be
v = 0.2x5
= 1.0 MG
umm , is it okay if we do this on microsoft word , cuz i cant send pics of answers here...
Answer:
composition of alpha phase is 27% B
Explanation:
given data
mass fractions = 0.5 for both
composition = 57 wt% B-43 wt% A
composition = 87 wt% B-13 wt% A
solution
as by total composition Co = 57 and by beta phase composition Cβ = 87
we use here lever rule that is
Wα = Wβ ...............1
Wα = Wβ = 0.5
now we take here left side of equation
we will get
= 0.5
= 0.5
solve it we get
Ca = 27
so composition of alpha phase is 27% B
Answer:
Explanation:adrive with visual acutity of 20/30 can just decipher asing adistance 20ft from asing determine the maximum destance from the sing which drivers with the flowing visual acuities will able to see the same sing 20/15 20/50