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3 years ago

Under which of the following conditions would a chemical reaction most likely proceed at the fastest rate?

Chemistry

2 answers:

Valentin [98]3 years ago

6 0

<h2>Answer:</h2>

Option A is correct

Adding an enzyme to decrease the activation energy of the reaction

<h2>Explanation:</h2>

Enzymes are the biological catalyst. They are proteins in nature. They are naturally found in humans,animals,micro-organisms,plants etc. They catalyze the chemical reactions by lowering activation energy and without being consumed in it.

boyakko [2]3 years ago

5 0

Answer: Option (a) is the correct answer.

Explanation:

An enzyme is defined as a substance which acts as a catalyst and it is produced by a living organism to bring about a specific biochemical reaction.

An enzyme actually helps in increasing the rate of a reaction by combining at a specific site and like a catalyst an enzyme does not get consumed in a chemical reaction.

An enzyme binds with the substrate and results in the formation of a stable enzyme-substrate complex.

Like a catalyst, an enzyme also helps in lowering the activation energy.

thus, we can conclude that adding an enzyme to decrease the activation energy of the reaction would make a chemical reaction most likely proceed at the fastest rate.

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3 years ago

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If a gas has a volume of 1000 ML at a temperature of 23°C and a pressure of 100 mmhg, what is it’s volume under standard conditi

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Answer:

119.7 mL.

Explanation:

From the general law of ideal gases:

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas (K).

For the same no. of moles of the gas at two different (P, V, and T):

P₁ = 100.0 mmHg, V₁ = 1000.0 mL, T₁ = 23°C + 273 = 296 K.

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3 years ago

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Answer:

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3 years ago

Why is the solar system often referred to as the sun’s family ?

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In each reaction box place the best reagent and conditions from the list below benzene 3 boxes

den301095 [7]

Answer : The correct answer is 1) AlCl₃ - CH₃Cl 2) HNO₃ -H₂SO₄ at room temperature 3) Fuming HNO₃ -H₂SO₄ at 90-100 ⁰ C heat .

I think this reaction is forming 2,4,6- trinitrotoluene from benzene, since the product is not mentioned. Following are the steps to convert Benzene to 2,4,6 trinitrotoluene .

Step 1: Conversion of Benzene to Toluene .

Benzene can be converted to toluene by Friedel Craft Alkylation of benzene . In this reaction reagent AlCl₃ and Ch3Cl is used . Electrophile CH³⁺ is produced which attached on carbon of benzene and formation of Toluene and HCl occur.

$Benzene \frac{AlCl3}{Ch3Cl}> Toulene + HCl$

Step 2 : Conversion of Toluene to dinitrotoluene.

Dinitritoluene is prepared from toluene by Nitration . This reaction uses Electrophilic substitution mechanism . The reagents used are HNO₃ and H₂SO₄ at room temperature . These reagents produces NO₂⁺ ( nitronium ion ), a electrophile which attacks on C2 and C4 Carbon atoms of Toluene.

Toluene $Tolune \frac{HNO3 -H2SO4}{30-40 degree C} -> 2,4- dinitrotoluene$

Step 3) Conversion of Dinitro toluene to trinitrotoluene.

This reaction is extended nitration of toluene . Further nitration is done in extreme condition . The temperature of reaction is increased to 90- 100 ⁰ C . Due to which there is more production of NO²⁺ ion occurs from HNO₃ -H₂SO₄ and they attack on C6 carbon atom of dinitrotoluene which forms 2,4,6- trinitrotoluene.

Dinitrotoluene $2,4 -dinitrotoluene \frac{fuming HNO3-H2So4}{90-100 C} -> 2,4,6-trinitrotoluene.$

So over all reaction uses three reagents in order :

$Benzene \frac{AlCl3}{CH3Cl} -> Toluene \frac{HNO3-H2So4}{room temp} -> 2,4-dinitrotoluene \frac{Fuming HNO3 -H2SO4}{Heating at 90-100 C} -> 2,4,6-trinitrotoluene .$

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