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Darina [25.2K]
2 years ago
8

What is the concentration of H+ ions at a pH = 2? mol/L What is the concentration of OH– ions at a pH = 2? mol/L What is the rat

io of H+ ions to OH– ions at a pH = 2? : 1
Physics
1 answer:
densk [106]2 years ago
4 0

Answer:

In Step 5, you will calculate H+/OH– ratios for more extreme pH solutions. Find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide for a solution at a pH = 2. Then divide the H+ concentration by the OH– concentration. Record these concentrations and ratio in Table C.

What is the concentration of H+ ions at a pH = 2?

0.01   mol/L  

What is the concentration of OH– ions at a pH = 2?

0.000000000001   mol/L  

What is the ratio of H+ ions to OH– ions at a pH = 2?

10,000,000,000 : 1

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

I LITERALLY spent 40 MINUTES trying to figure out this question, so please, use my VERY CORRECT answers!

I hope this helps!

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In Milgram's experiment:
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Define infer in science.
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Elevated water tanks are used in a municipal water distribution system to provide adequate pressure. Compute the height (h) of t
Lemur [1.5K]

Answer:

a)  h = 53.8 m,  b)   h_minimum = 28 m, h_maximum = 63.3 m

Explanation:

a) For this exercise let's use Bernoulli's equation.

The subscript 1 is for the tank and the subscript for the building

          P₁ + ½ ρ g v₁² + ρ g y₁ = P₂ + ½ ρ g v₂² + ρ g y₂

In general, the water tanks are open to the atmosphere, so P1 = Patm, also the tanks are very large so the speed of the water surface is very small v₁=0 and as they give us the precious static, this it is when the keys are closed so the output velocity is zero, v₂= 0. The height of the floors in a building is y₂ = 12 m

           

we substitute in Bernoulli's equation

         P_{atm} + 0 + ρ g h = P₂ + 0 + ρ g y₂

         h = \frac{(P_2 - P_{atm}) + \rho \ g \ y_2}{\rho \ g}

         h = \frac{\Delta P}{\rho g} + y₂

indicate that the value of ΔP = 410 10³ Pa

       

we calculate

           h = 410 10³ / (1000 9.8) + 12

           h = 53.8 m

b) ask for the height range for the minimum and maximum pressure

            h =\frac{\Delta P}{\rho g} ΔP / rho g

minimum

           h_minimum = 275 103/1000 9.8

           h_minimum = 28 m

maximums

           h_maximo = 620 103/1000 9.8

           h_maximum = 63.3 m

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