All categories

3 years ago

Which of these statements about a dipole are correct? Select all that are true.

Physics

1 answer:

krok68 [10]3 years ago

7 0

Answer:

• The electric field at any location in space, due to a dipole, is the vector sum of the electric field due to the positive charge and the electric field due to the negative charge.

• At a distance d from a dipole, where d >> 5 (the separation between the charges), the magnitude of the electric field due to the dipole is proportional to 1/d^3

• A dipole consists of two particles whose charges are equal in magnitude but opposite in sign

Explanation:

A dipole is a pair of magnetized, equal or oppositely charged poles the are being separated by a distance.

The statements about a dipole that are correct are:

• The electric field at any location in space, due to a dipole, is the vector sum of the electric field due to the positive charge and the electric field due to the negative charge.

• At a distance d from a dipole, where d >> 5 (the separation between the charges), the magnitude of the electric field due to the dipole is proportional to 1/d^3

• A dipole consists of two particles whose charges are equal in magnitude but opposite in sign

You might be interested in

A bird takes off from the tree and after 5 s is flying at a speed of 10 m/s. Calculate

Volgvan

Answer:

10miles/second

Explanation:

Change in velocity of the bird is expressed as the difference between the final velocity and initial velocity of the body.

Change in velocity = Final velocity - initial velocity

Since the bird takes off from the tree, the initial velocity of the bird = 0miles/sec

Final velocity = 10miles/secs

Change in velocity = 10-0

Change in velocity = 10miles/second

6 0

2 years ago

In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg. After the two

IrinaVladis [17]

This question involves the concepts of the law of conservation of momentum.

The magnitude of the final momentum of the eight ball is "0.22 N.s".

According to the law of conservation of momentum:

$P_{i1}+P_{i2}=P_{f1}+P_{f2}$

where,

$P_{i1}$ = initial momentum of the cue ball = 0.23 N.s

$P_{i2}$ = initial momentum of the eight ball = 0 N.s (since ball is initially at rest)

$P_{f1}$ = final momentum of the cue ball = 0.01 N.s

$P_{f2}$ = final momentum of the eight ball = ?

Therefore,

$0.23\ N.s + 0\N.s = 0.01\ N.s+P_{f2}\\\\P_{f2} = 0.22\ N.s$

Learn more about the law of conservation of momentum here:

brainly.com/question/1113396?referrer=searchResults

3 0

2 years ago

Suppose a current flows through a copper wire. Which two things occur?

worty [1.4K]

I’m pretty sure the answer is c and d hope this helps and good luck

3 0

2 years ago

Read 2 more answers

Two guitarists attempt to play the same note of wavelength 6.48 cmcm at the same time, but one of the instruments is slightly ou

k0ka [10]

The answer is λ₂ = 6.48 cm or 6.52 cm.

The out-of-tune guitar may have a wavelength between "6.48 cm" and "6.52 cm."

fb = |f2 − f1|

f₁ = 343/0.064

= 5276Hz

f₂ = 5276.9 Hz ± 17 Hz

f₂ = 5293.9 Hz or 5259.9 Hz

Now, calculating the possible wavelengths:

λ = 343/ 5259.9 or 343/ 5293.9

λ₂ = 6.48 cm or 6.52 cm

<h3>Why is beat frequency important?</h3>

When two waves with almost identical frequencies traveling in the same direction collide at a certain location, beats are produced. The opposing beneficial and harmful disruption causes the sound to alternatively be loud and weak whenever two sound waves with different frequencies reach your ear. This is referred to as beating.

The entire value of the frequency difference between the two waves is the beat frequency.

The following formula yields the beat frequency:

fb = |f2 − f1|

Learn more about beat frequency here:

brainly.com/question/14705053

#SPJ4

5 0

2 years ago

Read 2 more answers

At a distance of 0.208 cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 485 n/c . wh

Anna35 [415]

We have the equation for electric field E = kQ/ $d^{2}$