An electric bell is placed inside a transparent glass jar. The bell can be turned on and off using a switch on the outside of th
e jar. A vacuum is created inside the jar by sucking out the air. Then the bell is rung using the switch. What will we see and hear?
A) We’ll see the bell move, but we won’t hear it ring.
B) We won’t see the bell move, but we’ll hear it ring.
C) We’ll see the bell move and hear it ring.
D) We won’t see the bell move or hear it ring.
E) We’ll see the sound waves exit the vacuum pump.
A) We’ll see the bell move, but we won’t hear it ring.
B) We won’t see the bell move, but we’ll hear it ring.
C) We’ll see the bell move and hear it ring.
D) We won’t see the bell move or hear it ring.
E) We’ll see the sound waves exit the vacuum pump.
2 answers:
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Answer:
Impedance, Z = 107 ohms
Explanation:
It is given that,
Resistance, R = 100 ohms
Inductance,
Capacitance,
Frequency, f = 60 Hz
Voltage, V = 120 V
The impedance of the circuit is given by :
...........(1)
Where
is the capacitive reactance,
is the inductive reactance,
So, equation (1) becomes :
Z = 106.26 ohms
or
Z = 107 ohms
So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.