An electric bell is placed inside a transparent glass jar. The bell can be turned on and off using a switch on the outside of th
e jar. A vacuum is created inside the jar by sucking out the air. Then the bell is rung using the switch. What will we see and hear?
A) We’ll see the bell move, but we won’t hear it ring.
B) We won’t see the bell move, but we’ll hear it ring.
C) We’ll see the bell move and hear it ring.
D) We won’t see the bell move or hear it ring.
E) We’ll see the sound waves exit the vacuum pump.
A) We’ll see the bell move, but we won’t hear it ring.
B) We won’t see the bell move, but we’ll hear it ring.
C) We’ll see the bell move and hear it ring.
D) We won’t see the bell move or hear it ring.
E) We’ll see the sound waves exit the vacuum pump.
2 answers:
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Answer:
In Celsius:
Explanation:
The formula we are going to use is:
Where:
ε is the emissivity
σ is the Stefan constant
is the final temperature of surrounding surfaces
is the required temperature
is the are of surrounding surface
Calculating The area:
σ=
ε =0.95
=55+273
=328 K
=100 W
In Celsius:
is the equation that represents the Joule's law of heating.
Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to
1. Square of Current (I²),
2. Resistance of the conductor (R)
3. Time for which current is passed (t)
Hence, Heat generated = .....................(1)
By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).
...............................................(2)
From (2), Current (I) can be rewritten as
........................................................(3)
Substituting (3) in (1), we get