An electric bell is placed inside a transparent glass jar. The bell can be turned on and off using a switch on the outside of th
e jar. A vacuum is created inside the jar by sucking out the air. Then the bell is rung using the switch. What will we see and hear?
A) We’ll see the bell move, but we won’t hear it ring.
B) We won’t see the bell move, but we’ll hear it ring.
C) We’ll see the bell move and hear it ring.
D) We won’t see the bell move or hear it ring.
E) We’ll see the sound waves exit the vacuum pump.
A) We’ll see the bell move, but we won’t hear it ring.
B) We won’t see the bell move, but we’ll hear it ring.
C) We’ll see the bell move and hear it ring.
D) We won’t see the bell move or hear it ring.
E) We’ll see the sound waves exit the vacuum pump.
2 answers:
You might be interested in
Answer:
If I double the current in the inductor, the new total energy will become 4E (option f).
Explanation:
The coil or inductor is a passive component made of an insulated wire that stores energy in the form of a magnetic field due to its form of coiled turns of wire, through a phenomenon called self-induction. In other words, inductors store energy in the form of a magnetic field. The energy stored in the space where there is a magnetic field in the inductor is:
where E is Energy [J], L is Inductance [H] and I is Current [A].
If you double the current in the inductor, then the new value of the current is I'= 2*I. So replacing the new total energy is:
Then:
<em><u>If I double the current in the inductor, the new total energy will become 4E (option f).</u></em>
Given :
Number of operations move through a pocket calculator during a full day's operation , .
To Find :
How many coulombs of charge moved through it .
Solution :
We know , charge in one electron is :
So , charge on n electron is :
Therefore , -21.44 coulombs of charge is moved through it .
Hence , this is the required solution .