Answer:
The area of ∆DEF = 4.5in²
Step-by-step explanation:
From the above diagram,
∆BAC ~∆DEF
It is important to note that if two triangles are similar, the ratio of their areas is equal or equivalent to the ratio of the areas of their sides
This means for the above question, that
We have the bigger triangle = ∆BAC has a side of 4 in and Area = 8 in²
The small triangle has a side of 3in
Finding the scale factor k = ratio of the sides of both Triangles
k = 4/3
k² = (4/3)²
k² = 16/9
Hence,
Area of ∆BAC/ Area of ∆DEF = 16/9
8in²/Area of ∆DEF = 16/9
We cross Multiply
8 in² × 9 = Area of ∆DEF × 16
Divide both sides by 16
Area of ∆DEF = 72/16
= 4.5in²
Therefore, the Area of ∆DEF rounded to the nearest tenth = 4.5in²
<h3>The length of legs of isosceles right triangle is 8.5 cm</h3>
<em><u>Solution:</u></em>
Given is a isosceles triangle
hypotenuse = 12 cm
In an isosceles right triangle, the legs have equal lengths
Let these sides be each "a" cm
By pythogoras theorem,
Thus the length of leg of isosceles right triangle is 8.5 cm
$7.44
Hope I helped!!
giving me brainliest is much appreciated.. =)
Answer: It a permutation
Step-by-step explanation: Hope this help :D
145° is the correct answer
