If you are in an elevator that speed up then the apparent weight is
1 answer:
Answer:
Fnet - Fg
Explanation:
When an object is in an elevator, its weight varies with respect to the direction of movement of the elevator and the elevators acceleration.
The weight, W, of an object can be expressed as;
W = mg
where m is the object's mass, and g is the acceleration due gravity.
If the object is in an elevator that speed up, an apparent weight would be felt since both mass and elevator are moving against gravitational pull of the earth.
So that,
= mg + ma
where: mg is the weight of the object, and ma is the apparent weight.
Apparent weight (ma) = - mg
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By Considering the vertical distance and both vertical and horizontal final velocity, the time t = 0.45 s and Velocity V = 6.7 m/s
Given that a Veggie meatball with v = 5.0 m/s rolls off a 1.0 m high table.
Height h = 1.0 m
As the ball rolls off the table, it will be fallen under gravity. Where
g = 9.8 m/
Initial vertical velocity = 0
Initial horizontal velocity = 5 m/s
Considering the vertical distance, the formula to use to calculate the time will be;
h = ut + 1/2g
1 = 0 + 1/2 x 9.8
1 = 4.9
= 1/4.9
t =
t = 0.45 seconds
It takes 0.45 seconds to hit the floor if no one sneezes.
To calculate its velocity when it hits the floor, we will need to calculate for both vertical and horizontal final velocity and find the resultant velocity of the two.
Vertical component
=
+ gt
= 0 + 9.8(0.45)
= 4.41 m/s
Horizontal component
=
+ at
but a = 0
= 5 m/s
Final velocity V =
V = 6.67 m/s
Therefore, it will hit the floor at a velocity of 6.7 m/s
Learn more here: brainly.com/question/5063616