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rodikova [14]
2 years ago
5

What is the most important thing to remember about how to calculate Mechanical Energy?

Physics
1 answer:
nataly862011 [7]2 years ago
6 0

Answer:

The mechanical energy of a classical system is simply equal to the sum of its kinetic and potential energies.

E=T+V

Where the kinetic energy T is given by the equation

T=12mv2

and the potential energy V differs depending on whatever forces are acting on the system.

If the force acting on the object is gravity (a common case) the potential energy is given by

V(r)=GMmr

where the Ms represent the mass of the two interacting objects (The system and the earth, for example), r is the distance between their centers of mass, and G is the universal gravitational constant (=6.67e-11 N m^2 kg^-2)

In simple, close to earth, situations, it takes the simpler form

V=mgh

Where m is the mass of the system, g the gravitational acceleration, and h the height.

Another well-known and important potential energy is that for a spring that obeys Hooke's law.

V(x)=12kx2

The potential energy can otherwise be calculated from its definition; the value of potential energy at a point in space is equal to the negative of the Work needed to bring the object to that point from an arbitrarily chosen reference point in space, which is generally chosen so that the potential energy will never be negative.

This is a very broad question. The most broad answer i can give is that energy (mechanical, potential, chemical, etc...) can all be measured in Joulse. This is a unit for energy. Work and energy are the same, and work is defined as force (mass * acceleration) times a distance. The base unit of force is Newtons (1kg * (9.81 meters / second^2)) and for distance it is Meters, furthermore one joule of energy is equal to one Newton-Meter. There, now we know that one joule of energy is equivalent to moving 1 kilogram of mass at 9.81 m/s^2 over a distance of 1 meter; or any such manipulation of the

It seems, that you lack knowledge of Physics and Mathematics.

Go to Ramamurti Shankar “Fundamental Physics I” on You Tube and try to follow Prof. Shankar. I know no better teacher. Just watch the videos until you have understood all the remarks and expanations. Do not learn formulas by heart; do learn the logic of how to derive those formulas. Try to understand the Principles of Physics. Do not fool yourself. Work seriously and honestly. Use your logic and try to fix your logic. (I hope that you understand what I am talking about.)

With lesson 12–15 of “Fundamental Physics I” you will get the best introduction to Special Relativity Theory. The Lorentz Transformation are just beautiful and … everything follows from them. It will take you only 5 hours if you are smart.

Have you another question ?

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Alex
Hello there,
400 meters= 0.4 km
Time= Distance / speed
        = 0.4 / 69
        = 0.0057971014492754 hr
        = 0.35 min

Hope this helps :))

~Top
 
8 0
3 years ago
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At the same instant that a 0.50-kg ball is dropped from 25 m above Earth, a second ball, with a mass of 0.25 kg, is thrown strai
zhannawk [14.2K]

Answer:

The center of mass of the two-ball system is 7.05 m above ground.

Explanation:

<u>Motion of 0.50 kg ball:</u>

Initial speed, u = 0 m/s

Time = 2 s

Acceleration = 9.81 m/s²

Initial height = 25 m

Substituting in equation s = ut + 0.5 at²

                 s = 0 x 2 + 0.5 x 9.81 x 2² = 19.62 m

Height above ground = 25 - 19.62 = 5.38 m

<u>Motion of 0.25 kg ball:</u>

Initial speed, u = 15 m/s

Time = 2 s

Acceleration = -9.81 m/s²

Substituting in equation s = ut + 0.5 at²

                 s = 15 x 2 - 0.5 x 9.81 x 2² = 10.38 m

Height above ground = 10.38 m

We have equation for center of gravity

          \bar{x}=\frac{m_1x_1+m_2x_2}{m_1+m_2}

          m₁ = 0.50 kg

          x₁ = 5.38 m        

          m₂ = 0.25 kg

          x₂ = 10.38 m    

Substituting

         \bar{x}=\frac{0.50\times 5.38+0.25\times 10.38}{0.50+0.25}=7.05m

The center of mass of the two-ball system is 7.05 m above ground.  

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Which of the following electromagnetic waves has the shortest wavelength?
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What do electric forces between charges depend on
denis23 [38]

Answer:

On the magnitude of the charges, on their separation and on the sign of the charges

Explanation:

The magnitude of the electric force between two charges is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

From the formula, we see that the magnitude of the force depends on the following factors:

- magnitude of the two charges

- separation between the charges

Moreover, the direction of the force depends on the sign of the two charges. In fact:

- if the two charges have same sign, the force is repulsive

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