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xz_007 [3.2K]
2 years ago
6

What is the slope for each for each line y=1/2x-4 y=2x-3

Mathematics
2 answers:
Vedmedyk [2.9K]2 years ago
7 0
Slope= 1/2
Slope= 2
Those are the slopes in those equations. Hope that helps!
valentina_108 [34]2 years ago
3 0

Answer:

1. m = 1/2

2. m = 2

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RideAnS [48]

Answer:

2 Hours

Step-by-step explanation:

14+6+6 = 26.

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2 years ago
The tables below show the values of Y for different values of X
pogonyaev

Answer:

Option D

Step-by-step explanation:

Rate of change of a linear function between two points (x_1,y_1) and (x_2,y_2) is given by,

Rate of change 'm' = \frac{y_2-y_1}{x_2-x_1}

From the given table,

Rate of change of the function between (-2, 6) and (-4, 9),

Rate of change 'm' = \frac{9-6}{-4-(-2)}

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Initial value = y-intercept

Let the equation of the line passing through a point (h, k) is,

y - k = m(x - h)

If a point (-2, 6) is lying on the graph of the function,

y - 6 = -\frac{3}{2}(x+2)

y = -\frac{3}{2}x-3+6

y = -\frac{3}{2}x+3

Y-intercept of the function = 3

Therefore, initial value of the function = 3

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3 0
2 years ago
What is the oblique asymptote of the function f(x) x^2+x-2/x+1
Mamont248 [21]
f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}


\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
=0

Consequently, t<span>he limit of f(x) as x approaches infinity is x.

In other words, f(x) approaches the line y=x, 
</span><span>
so oblique asymptote is y=x.

I'm Japanese, if you find some mistakes in my English, please let me know.</span>

3 0
3 years ago
Please answer asap!!!!!!!!!!!!!!!!!!!!!!!!!
Vilka [71]

Answer:

x=60

Step-by-step explanation:

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4 0
2 years ago
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