The probability that the first success occurs on the third trial is 0.125.
Answer: Option C
<u>Step-by-step explanation:</u>
The probability of success is given by the geometric distribution formula:
Where,
p = probability of success for single trial.
q = probability of failure for a single trial (1-p)
x = the number of failures before a success.
P(X = x) = Probability of x successes in n trials.
<u>Given: </u>
p = 19% = 0.19
q = 1 – p = 1 – 0.19 = 0.81
x = 3
We want to find the probability that the first success occurs on the third trial so,