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Blababa [14]
3 years ago
9

A rotating space station is said to create "artificial gravity" - a loosely-defined term used for an acceleration that would be

crudely similar to gravity. The outer wall of the rotating space station would become a floor for the astronauts, and centripetal acceleration supplied by the floor would allow astronauts to exercise and maintain muscle and bone strength more naturally than in non-rotating space environments. If the space station is 200 m in diameter, what angular velocity would produce an "artificial gravity" of 9.80 m/s^2 at the rim?
Physics
1 answer:
Anestetic [448]3 years ago
5 0

Answer:

ω = 0.313 rad/s

Explanation:

D = 200 m ⇒  R = D / 2 = (200 m / 2) = 100 m

ac = 9.8 m/s²

The following equation can be used

ac = ω²*R    ⇒    ω = √(ac / R)

then we insert the values in the last formula

ω = √(9.8 m/s² / 100 m) = 0.313 rad/s

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The acceleration of the crate after it begins to move is 0.5 m/s²

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Normal reaction (N) = mg = 50 × 10 = 500 N

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Fբ = μN

Fբ = 0.15 × 500

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Frictional force (Fբ) = 75 N

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Mass (m) = 50 Kg

Net force (Fₙ) = 25 N

<h3>Acceleration (a) =?</h3>

a = Fₙ / m

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