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1 year ago

I NEED TOUR HELP, PLEASE.

Chemistry

1 answer:

kvasek [131]1 year ago

8 0

It would be 5.0 more in i did this

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HELP UNDERSTAND, PLEASE!

cestrela7 [59]

My best guess has to be 1:3

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2 years ago

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Bob and Ada are camping and have sweet potatoes wrapped in foil to eat. Ada put her sweet potato in the bonfire for a while, but

Ahat [919]

Answer: one of the sweet potatoes atoms are moving really fast and the other sweet potatoes atoms isn't moving.

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2 years ago

A student carried out a simple distillation on a compound known to boil at 124 oc and they reported a boiling point of 116-117 o

chubhunter [2.5K]

Answer :

The correct answer is due to incorrect position of thermometer .

Distillation is process of separating two volatile liquids on the basis of their boiling points .In involves the following set up ( shown in image )

Since the Boiling point is found is 116-117 C which is near to 124 C , also the purity was checked and thermometer was calibrated .

So the only error could be possible is position of thermometer .

The position of bulb of thermometer is very important to get an accurate reading of boiling point .The vapor so formed should touch the side walls of bulb as soon as they are formed .

May be the bulb of thermometer was kept far from the vapors formed by liquid so, s<u>ome of the vapor before reaching to bulb start condensing and their Temperature decreases </u>.

Hence , the temperature shown by thermometer was decrease than actual boiling point due to incorrect position of thermometer.

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2 years ago

Which of the following could be classified as unleavened bread?

san4es73 [151]

Answer:

Tortilla

Explanation:

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2 years ago

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Equal volumes of two solutions, one containing a strong acid at pH 2 and the other containing a strong base at pH 12, are mixed.

mash [69]

Answer:

Explanation:

Assume we have 1 L of each solution.

Solution 1

$\text{[H$^{+}$]}= 10^\text{-pH} \text{ mol/L} = 10^{\text{-2}} \text{ mol/L}\\ \text{ moles of H}^{+} = \text{ 1 L solution} \times \dfrac{10^{-2}\text{ mol H}^{+}}{\text{1 L solution}} = 10^{-2}\text{ mol H}^{+}$

Solution 2

pH = 12

pOH = 14.00 - pOH = 14.00 - 12 = 2.0

$\text{[OH$^{-}$]}= 10^\text{-pOH} \text{ mol/L} = 10^{\text{-2}} \text{ mol/L}\\ \text{ moles of OH}^{-} = \text{ 1 L solution} \times \dfrac{10^{-2}\text{ mol OH}^{-}}{\text{1 L solution}} = 10^{-2}\text{ mol OH}^{-}$

3. pH after mixing

H⁺ + OH⁻ ⟶ H₂O

I/mol: 10⁻² 10⁻²

C/mol: -10⁻² -10⁻²

E/mol: 0 0

The H⁺ and OH⁻ have neutralized each other. The pH will be that of pure water.

pH = 7

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2 years ago