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Salsk061 [2.6K]
3 years ago
14

The Earth's period of revolution is 365.25 days. Convert this period of revolution into hours

Chemistry
1 answer:
Helga [31]3 years ago
4 0
8,766 hours is your answer :)
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The reaction in Fe + O2→Fe2O3 is an example of a(n): A. combination reaction. B. decomposition reaction. C. aqueous reaction. D.
motikmotik
This is a combination reaction because two molecules becomes one

A + B ---> AB
8 0
3 years ago
Calcium carbonate is a compound that is used to make chalk for drawing on rocks or pavement. One molecule has one atom of calciu
Black_prince [1.1K]

Answer:

the chemical formula is caca3

6 0
3 years ago
Read 2 more answers
A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate
Zarrin [17]

Answer: Empirical formula is C_2H_5O

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = \frac{330g}{12g/mol}=27.5moles

Moles of Hydrogen = \frac{69.5g}{1g/mol}=69.5moles

Moles of Oxygen = \frac{220.2g}{16g/mol}=13.76moles

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2

\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5

\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = C_2H_5O

7 0
3 years ago
What mass of each solute is present in 294 g of a solution that contains 4.86% by mass NaCl and 7.54% by mass Na2CO3
Angelina_Jolie [31]
In order to compute the mass of each solute in the sample, we simply multiply the percentage mass of each solute with the total mass of the solution. This is ad such:
Mass (NaCl) = 0.0486 x 294
Mass (NaCl) = 14.29 grams

Mass(Na₂CO₃) = 0.0754 x 294
Mass(Na₂CO₃) = 22.17 grams
7 0
3 years ago
HELPPp now plsss I really need help !!!!!
blondinia [14]

Answer:

The Forces that form each star would be your answer :)

5 0
2 years ago
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