Answer:
Kc = 77.9
Explanation:
To solve this equilibrium problem we will use an ICE Chart. We recognise 3 stages: Initial (I), Change (C) and Equilibrium (E). We complete each row with the <em>concentration or change of concentration in that stage</em>. Since the container is of 1.00 L, the initial concentrations are [NO] = 0.103 M and [Br₂] = 9.75 × 10⁻² M and the equilibrium concentration of Br₂ is 6.21 × 10⁻² M. Then,
2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)
I 0.103 9.75 × 10⁻² 0
C -2x -x +2x
E 0.103 -2x 9.75 × 10⁻² - x 2x
Also, we know that
[Br₂]eq = 9.75 × 10⁻² - x = 6.21 × 10⁻² ⇒ x = 3.54 × 10⁻² M
We can use the value of x to find the concentrations at equilibrium:
[NO] = 0.103 -2x = 0.103 - 2 . 3.54 × 10⁻² = 3.22 × 10⁻² M
[Br₂] = 6.21 × 10⁻² M
[NOBr] = 2x = 2 . 3.54 × 10⁻² = 7.08 × 10⁻² M
We can use these concentrations in the equilibrium constant (Kc) expression.
Cleaning products
stomach acid
The empirical formula can be C₄H₈ or CH₃-CH=CH-CH₃.
Explanation:
As the number of moles of each element is already given ,then there is no need of further calculations. We can get the empirical formula by writing the moles of each element in its subscript position. As empirical formula is one of the simplest way to represent any chemical compound. So the given compound can be written as CₓHₙ. Here x and n are the number of moles of carbon and hydrogen present in the compound.
Since it is stated as the 4 moles of Carbon and 8 moles of hydrogen is present and it is known that each carbon can have maximum four single bond with its neighbors, so the empirical formula can be written as
C₄H₈ or CH₃-CH=CH-CH₃
Thus, the empirical formula can be C₄H₈ or CH₃-CH=CH-CH₃.
Answer:
The first part of his theory states that all matter is made of atoms, which are indivisible. The second part of the theory says all atoms of a given element are identical in mass and properties. The third part says compounds are combinations of two or more different types of atoms.
Explanation:
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