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2 years ago

Multiply and simplify: (2b2+2b)2

Mathematics

1 answer:

sveta [45]2 years ago

4 0

Answer:

4b^2+2b (b^2 means b squared)

Step-by-step explanation:

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How do i do 2x8 and don’t just tell me the answer i need someone to explain pls

Sonja [21]

Answer:

Step-by-step explanation:

2 x 8 is just another way of saying what would 8 + 8 be

for example, 5x5 would just 25 but 5+5+5+5+5 would also be 25

Hope this helps, sorry im not a good teacher:)

5 0

2 years ago

What is 5 3/8 as a inproper fracon and as a mixed number

ICE Princess25 [194]

$\frac{53}{8}$
To divide 53 by 8 wont be possible so u find a number that when you multiply by 8 it gives u a number closer to 58 which is 8*6=48 i.e 53 divided by 8 is 6 rem, then to get the reminder you subtract 42 from 53 i.e 53–48=5 so the final answer will be 6 and 5/6

3 0

2 years ago

I NEED HELP PLZ I WILL GIVE THANKS AND BRAINLIST

strojnjashka [21]

Answer:

The answer is D

Step-by-step explanation:

D is the point where the two lines intersect and therefore it is the solution of the line

7 0

2 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

5 months ago

Fatima is shading this model to show 0.08x3 . shade the correct amount of boxes that will show the product

Karo-lina-s [1.5K]

Shade 0.08 3 times

In total that's 24 hundreths to shade

For more help, please upload a picture

Hope this helps!!

7 0

2 years ago