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Cloud [144]
2 years ago
5

I need help can I have how to do it and some work so I can do it.

Mathematics
1 answer:
Delicious77 [7]2 years ago
5 0

Answer:

im guessing you're trying to find where the lines will meet at, so the lines will meet at (1,-1)

Step-by-step explanation:

sadly it doesnt allow me to add in a photo but ill tell you a good enough explanation of what to draw, for y=3x+2 your line starts at 2 on the y axis and goes down (-3/1)

for y=3x-4 your line starts at -4 and go up by 3/1

hope this helped, not sure if you need anything more.

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The symbols <, >, ≤, ≥ are called
AlekseyPX

Given:

The symbols ,\leq ,\geq.

To find:

The correct name for the given group of symbols.

Solution:

We know that,

Equality symbols is "=".

Inequalities symbols are ",\leq ,\geq".

Operational signs are +,-,\times , \div.

Radical signs is \sqrt{}.

It means, the symbols ,\leq ,\geq are called inequalities symbols.

Therefore, the correct option is B.

7 0
3 years ago
The J.R. Ryland Computer Company is considering a plant expansion to enable the company to begin production of a new computer pr
Solnce55 [7]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

Medium-Scale Large-Scale

Expansion Profit Expansion Profit

x f(x) y f(y)

Low 50 0.2 0 0.2

Demand Medium 150 0.5 100 0.5

High 200 0.3 300 0.3

a. Compute the expected value for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of maximizing the expected profit?

Expected value for medium scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(50 * 0.2) + (150 * 0.5) + (200 * 0.3)]

= 145

Expected value for Large scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(0 * 0.2) + (100 * 0.5) + (300 * 0.3)]

= 140

Medium scale expansion profit is preferred as it has the highest expected value.

b. Compute the variance for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of minimizing the risk or uncertainty?

Variance (V) = Σ(X - E)² * f(x):

Variance for medium scale expansion profit :

V = [((50-145)^2 * 0.2) + ((150-145)^2 * 0.5) + ((200-145)^2 * 0.3) = 2725

Variance for Large scale expansion profit :

V = [((0-140)^2 * 0.2) + ((100-140)^2 * 0.5) + ((300-140)^2 * 0.3) = 12400

Smaller variance is required to minimize risk, Hence, choose the medium scale expansion profit.

3 0
3 years ago
PLEASE HELP <br> This table contains an Arithmetic Sequence. Find the missing terms in the table.
damaskus [11]
2=^? Zlon square right
7 0
2 years ago
Fernando invested money in a 4-yr CD (certificate of deposit) that returned the equivalent of 5.2% simple interest. He invested
Andrew [12]

Answer: $5000; $2000

Step-by-step explanation:

Simolw interest is calculated as: PRT/100

where,

P = principal

R = rate

T = time

Let the money in the 4-yr cd be represented by y.

Since rate = 5.2%

Simple interest = (y × 5.2 × 4)/100

Since he invested $3000 less in a 18-month CD, Let the money in the 18-month CD be represented by (y - $3000).

Then, S.I = [(y - $3000) × 3 × 1.5]/100

The total interest = $1130

We then equate the two simple interest together. This will be:

= (y × 5.2 × 4)/100 + (y - $3000) × 3 × 1.5]/100 = $1130

0.208y + 0.045(y - $3000) = $1130

0.208y + 0.045y - $135 = $1130

0.253y = $1130 + $135

0.253y = $1265

y = $1265/0.253

y = $5000

The money invested in 4-yr CD = $5000

The money invested in the 18-month CD = $5000 - $3000 = $2000

8 0
3 years ago
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IceJOKER [234]

Answer:

dV/dt = 40π

Step-by-step explanation:

We are told that The radius r(t) of the base of a cone is increasing at a rate of 10 meters per second. Thus;

dr/dt = 10 m

Height: h = 6 m

Volume of cone is given by the formula;

V = ⅓πr²h

dV/dr = ⅔πrh

We want to find the rate at which the volume is changing at radius of 1m.

Thus;

dV/dt = (dV/dr) × (dr/dt)

dV/dt = ⅔π(1 × 6) × (10)

dV/dt = 40π

8 0
3 years ago
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