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Cloud [144]
2 years ago
5

I need help can I have how to do it and some work so I can do it.

Mathematics
1 answer:
Delicious77 [7]2 years ago
5 0

Answer:

im guessing you're trying to find where the lines will meet at, so the lines will meet at (1,-1)

Step-by-step explanation:

sadly it doesnt allow me to add in a photo but ill tell you a good enough explanation of what to draw, for y=3x+2 your line starts at 2 on the y axis and goes down (-3/1)

for y=3x-4 your line starts at -4 and go up by 3/1

hope this helped, not sure if you need anything more.

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Which one is the right one? Help me please.
frez [133]

Answer:

90 km/h

Step-by-step explanation:

To solve this problem you first need to convert minutes to hours since the unit is km/h. Doing this we get half an hour (1 hour=60 mins so you divide 30 by 60) after converting you simply divide 45 by 1/2 or .5 to get the answer.

4 0
3 years ago
Kyra started with the number 56.8. If she ended with 568what did she do to the number
svet-max [94.6K]
Wow this ones easy.....Your in high school and i'm in middle school LOL...I'll answer the question.You have to <span>multiplied it by 10</span>
4 0
3 years ago
Read 2 more answers
Help me plz!!!!!!!!!!!
Elena-2011 [213]
Vinegar*16=water
water/16=vinegar

A.
if vinegar is 1/4 then
1/4 times 16=4=water
4 cups



B. 8oz=1cup
80 oz water
water/16=vinegar
80/16=5oz=vinegar
5oz

C.
1qt vinegar
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3 0
3 years ago
Explain how to solve the equation and then check the solution.
mihalych1998 [28]

Answer:

q=13

Step-by-step explanation:

Solve  :    -q+13 = 0  

Subtract  13  from both sides of the equation :  

                     -q = -13

Multiply both sides of the equation by (-1) :  q = 13

6 0
2 years ago
Read 2 more answers
Help me fjfjsncjdhdhfh​
Deffense [45]

Step-by-step explanation:

=>  2 {x}^{2}  +  \frac{7}{2}x +  \frac{3}{4}  = 0

=> \frac{8 {x}^{2}  + 14x + 3}{4} = 0

=> 8 {x}^{2}  + 14x + 3 = 0

=> 8 {x}^{2}  + 12x + 2x + 3 = 0

=> 4x(2x + 3) + 1(2x + 3) = 0

= > (2x + 3)(4x + 1) = 0

=  > x =  -  \frac{3}{2} or \frac{ - 1}{4}

option C

8 0
3 years ago
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