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creativ13 [48]
3 years ago
11

the lewis dot structure rule states that S=N-A. recall that A represents the TOTAL number of valence electrons available from al

l the atoms in molecule. what is A from silicon tetrachloride, SiCL4
Chemistry
1 answer:
Afina-wow [57]3 years ago
6 0

Answer: oh i thought i knew it nvm im sorry love

Explanation:

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Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta
Vilka [71]

Answer:

147.2g

Explanation:

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8 0
3 years ago
Ammonia, nh3, is a weak base with a kb = 1.8 x 10-5. in a 0.8m solution of ammonia, which has a higher concentration: ammonia (n
insens350 [35]
Answer is: concentration ammonia is higher than concentration of ammonium ion.
Chemical reaction of ammonia in water: NH₃ + H₂O → NH₄⁺ + OH⁻.
Kb(NH₃) = 1,8·10⁻⁵.
c₀(NH₃) = 0,8 mol/L.
c(NH₄⁺) = c(OH⁻) = x.
c(NH₃) = 0,8 mol/L - x.
Kb = c(NH₄⁺) · c(OH⁻) / c(NH₃).
0,000018 = x² /  0,8 mol/L - x.
solve quadratic equation: x = c(NH₄⁺) = 3,79·10⁻³ mol/L.
7 0
3 years ago
I need help with this
cricket20 [7]

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7 0
2 years ago
Read 2 more answers
As a real gas deviates from ideal gas behavior, the particles _____
Alik [6]

Answer:

Have some attraction towards each other

Explanation:

Gases deviate from the ideal gas behavior because their molecules have forces of attraction between them. At high pressure, the molecules of gases are very close to each other so the molecular interactions start operating and these molecules do not strike the walls of the container with full impact.

Hope this helps :-)

Have a great rest of your day or night!

Enjoy your studies and assignments

<3 simplysun

ps. I do not own any of these answers so please don't give full credit to me

7 0
3 years ago
Borane (BH3) adds to alkenes to form an alkylborane. In the first box draw the mechanism arrows, and in the second box draw the
OLEGan [10]

Answer:

The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.

Explanation:

The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.

6 0
3 years ago
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