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aksik [14]
2 years ago
9

What is the weight of oxygen in 50gwater​

Chemistry
1 answer:
8_murik_8 [283]2 years ago
5 0

To compute the required mass of the element to form the given molecules, we'll use the general formula shown below:

{eq}\displaystyle m_1=\frac{M_1}{M_2}\times m_2 {/eq}, where,

{eq}M_1 {/eq} is the molecular weight of the element.

{eq}M_2 {/eq} is the molecular weight of the given molecule.

{eq}m_2 {/eq} is the mass of the given molecule.

Answer and Explanation:

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The given value is:

The value of the mass of the water molecule is {eq}m_2=\rm 50\ grams {/eq}.

The chemical reaction for the formation of water...

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Formula for Mass: Definition & Examples

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Chapter 28 / Lesson 42

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What is mass? Learn the mass definition and how to find the mass of an object using the mass formula. See common mass characteristics and properties.

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Chlorine has two naturally occurring isotopes, 35C1 Gsotopic mass 34.9689 amu) and 370 (isotopic mass 36.9659 amu). If chlorine
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<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 75.77% and 24.23% respectively.

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Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

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Mass of _{17}^{35}\textrm{Cl} isotope = 34.9689 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

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Mass of _{17}^{37}\textrm{Cl} isotope = 36.9659 amu

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