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What percentage of the mass of hydrofluoric acid (HF) is contributed by hydrogen?

Morgarella [4.7K]

This problem is asking for the percent by mass of hydrogen in hydrofluoric acid. At the end, the answer turns out to be D. 5% as shown below:

<h3>Percent compositions:</h3>

In chemistry, percent compositions are used for us to know the relative amount of a specific element in a compound. In order to do so for hydrogen, we use the following formula, which can also be applied to any other element in a given compound:

$\% H=\frac{m_H*1}{M_{HF}}*100\%$

Where $m_H$ stands for the atomic mass of hydrogen and $M_{HF}$ for the molar mass of hydrofluoric acid. In such a way, we plug in the atomic masses of hydrogen (1.01 g/mol) and fluorine (19.0 g/mol) to obtain:

$\% H=\frac{1.01g/mol*1}{1.01g/mol+19.0g/mol}*100\%\\\\\% H=5\%$

Learn more about percent compositions: brainly.com/question/12247957

5 0

2 years ago

Explain why each mineral has its own properties, different from every other mineral

kaheart [24]

Each mineral has its own properties different from other minerals because minerals are made up of different elements. Different elements which can be found on the periodic table all have unique properties, therefore, gold will have distinct properties in comparison with zinc or aluminium for example because they are made up of different elements :))))
I hope this is helpful
have a nice day

4 0

3 years ago

What property of water is primary for living organisms? (SC.6.E.7.4) *

katrin [286]

Answer:

It is liquid at most temperatures on Earth.

8 0

3 years ago

Why can water be used in the cooling system of a car? A. it always heats the car in the winter B. it helps fluctuate temperature

JulsSmile [24]

The answer is C. It resists fast temperature change

8 0

3 years ago

Read 2 more answers

When 10.0 grams of ch4 reacts completely with 40.0 grams of o2 such that there are no reactants left over, 27.5 grams of carbon

Zina [86]

The balanced equation for the reaction is :-

CH₄(g) + 2O₂(g) ---------> CO₂(g) + 2H₂O(l)

Molar mass of CH₄ = 16 g/mole

Molar mass of O₂ = 32 g/mole

Molar mass of H₂O = 18 g/mole

Molar mass of CO₂ = 44 g/mole

Now we calculate the number of moles of reactants,

moles of CH₄ = mass of CH₄/molar mass of CH₄ = 10/16 = 0.625

Moles of O₂ = mass of O₂/molar mass of O₂ = 40/32 = 1.25

Now, as per the balanced reaction, for complete reaction to occur, one mole of CH₄ require 2 moles of O₂

Thus, 0.625 moles of CH₄ requires 1.25 moles of O₂

both CH₄ and O₂ are present in the exact required quantity.

Hence, moles of CO₂ formed = moles of CH₄ reacted = 0.625

Mass of CO₂ formed = moles of CO₂ x Molar mass of CO₂ = 0.625 x 44 = 27.5g

Moles of H₂O formed = moles of O₂ reacted = 1.25g

<span>Thus, mass of H</span>₂O formed = moles of H₂O x molar mass of H₂O = 1.25 x 18 = 22.5g

8 0

3 years ago