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3 years ago

For the reaction below, which change would cause the equilibrium to shift to the right? EXPLAIN.

Chemistry

1 answer:

Mice21 [21]3 years ago

6 0

Answer:

C. Decrease the concentration of hydrogen gas

Explanation:

<u><em>Decreasing the concentration of hydrogen gas</em></u><em> would cause the equilibrium to shift to the right.</em>

According to Le Chatelier's principle, when a reaction is in equilibrium and one of the constraints affecting reactions is varied, the equilibrium will shift so as to annul the effects of the change.

Decreasing the concentration of dihydrogen sulfide will cause the equilibrium to shift to the left because as reactants are removed, more of the reactants would be formed.

Increasing the pressure of the system will also cause the equilibrium to shift to the left because the total number of moles of reactants is less than that of products. Hence, more of reactants would be formed with increased pressure.

Increasing the concentration of carbon disulfide will cause the equilibrium to shift to the left because as more of the products are added into the reaction, more of the reactants will begin to form.

<u>The only reason for the equilibrium to shift to the right causing more of the products to be formed is decreasing the concentration of hydrogen gas which happens to be one of the products. As more of the products are removed from the reaction, the equilibrium will shift to ensure that more products are formed.</u>

The correct option is C.

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<h3>What is current?</h3>

Current in an electrochemical cell is the ratio of the quantity of electricity in columns and time in seconds.

Given,

Current (I) = 0.350 A

Time = 21.7 hours

Molar mass of chromium = 52.0 g/mol

First time is converted into seconds:

1 hour = 3600 seconds

21.7 hours = 76020 seconds

The quantity of electricity flowing in the electrochemical solution is calculated as:

$\begin{aligned} \rm Q & = \rm It\\\\& = 0.350 \times 76020 \\\\& = 26607\;\rm C \end{aligned}$

Electricity required for depositing 1 mole or 52.0 g chromium is calculated as:

In electrochemical solution, chromium chloride is dissociated as:

$\rm CrCl_{2} \rightarrow Cr^{2+} + 2 Cl^{-} \\\\\rm Cr^{2+} +2 e^{-} \rightarrow Cr$

Two moles of electrons are needed to deposit 52.0 g of chromium.

If, 1 electron = 96500 C

Then, 2 electron = 193000 C

The mass of chromium deposited is calculated as:

193000 C = 52 g chromium

So, 26607 C = $\dfrac{26607 \times 52}{193000} = 7.17 \;\rm gm$

Therefore, 7.17 gm of chromium is produced.

Learn more about an electrochemical cell here:

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