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3 years ago

For the reaction below, which change would cause the equilibrium to shift to the right? EXPLAIN.

Chemistry

1 answer:

Mice21 [21]3 years ago

6 0

Answer:

C. Decrease the concentration of hydrogen gas

Explanation:

Decreasing the concentration of hydrogen gas would cause the equilibrium to shift to the right.

According to Le Chatelier's principle, when a reaction is in equilibrium and one of the constraints affecting reactions is varied, the equilibrium will shift so as to annul the effects of the change.

Decreasing the concentration of dihydrogen sulfide will cause the equilibrium to shift to the left because as reactants are removed, more of the reactants would be formed.

Increasing the pressure of the system will also cause the equilibrium to shift to the left because the total number of moles of reactants is less than that of products. Hence, more of reactants would be formed with increased pressure.

Increasing the concentration of carbon disulfide will cause the equilibrium to shift to the left because as more of the products are added into the reaction, more of the reactants will begin to form.

The only reason for the equilibrium to shift to the right causing more of the products to be formed is decreasing the concentration of hydrogen gas which happens to be one of the products. As more of the products are removed from the reaction, the equilibrium will shift to ensure that more products are formed.

The correct option is C.

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What are the groups on the periodic table let us predict how elements will react

cluponka [151]

Answer:

The vertical columns are called groups.

Explanation:

Periodic table consist of vertical columns and horizontal rows.

Vertical columns are called groups while horizontal rows are called periods.

There are seven periods and 18 groups in periodic table.

The elements in same group have similar properties and can react in a similar way.

The elements in same group have same number of valance electrons that's why their reactivity is same.

Consider the example of alkaline earth metals. They are present in group two and have same number of valance electrons (two valance electrons).

They react with oxygen and form oxide.

2Ba + O₂ → 2BaO

2Mg + O₂ → 2MgO

2Ca + O₂ → 2CaO

this oxide form hydroxide when react with water,

BaO + H₂O → Ba(OH)₂

MgO + H₂O → Mg(OH)₂

CaO + H₂O → Ca(OH)₂

With sulfur,

Mg + S → MgS

Ca + S → CaS

Ba + S → BaS

7 0

3 years ago

How would you make a 2.00L of 0. 500M sodium chloride solution. (assume you have a fully equipped lab with water); sketch, calc

Gwar [14]

Answer:

Sodium chloride solution:

First you need to calculate the mass of salt needed (done in the explanation), which is 58.44g. Then it have to be weighted in an analytical balance in a weighting boat and then transferred into a 2L volumetric flask that is going to be filled until the mark with distilled water.

Sulfuric acid dilution:

First you need to calculate the volume needed (done in the explanation), it is 16.6 mL. Using a graduated pipette one measures this volume and transfer it into a 2L volumetric flask that is already half filled with distilled water, and then one fills it until its mark.

Explanation:

Sodium chloride solution:

Each liter of a 0.500M solution has half mol, so 2L of said solution has 1 mol of salt. Sodium chloride molar mass is 58.44g/mol, so in 2L of solution there is 58.44g of salt. That`s the mass that`s going to be weighted and transferred to a 2L volumetric flask.

Sulfuric acid dilution:

This is the equation for dilution of solutions:

$c_{1} v_{1} =c_{2} v_{2}$

Where "c1" stands for the initial concentration (stock solution concentration), "v1" for the initial volume (volume of stock solution used), "c2" for the desired concentration and "v2" for the desired volume.

When we are diluting from a stock solution we want to know how much do we have to pipette from the stock solution into our volumetric flask. We do so by isolating the "v1" term from the dilution equation:

$v_{1} =\frac{c_{2} v_{2} }{c_{1} }$