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Mumz [18]
2 years ago
7

How many grams of iron (Fe) would be needed to generate 5.25 g of hydrogen gas (H2)?

Chemistry
1 answer:
Free_Kalibri [48]2 years ago
8 0

Considering the given reaction, 109 g of Fe are needed to generate 5.25 g of H₂.

<h3>What is stoichiometry?</h3>

Stoichiometry refers to the relationship between the quantities of reactants and products before, during, and following chemical reactions.

  • Step 1: Write the balanced equation.

3 Fe + 4 H₂O ⇒ 4 H₂ + Fe₃O₄

  • Step 2: Calculate the mass of Fe needed to produce 5.25 g of H₂.

We will consider the following relationships.

  1. The molar mass of Fe is 55.85 g/mol.
  2. The molar ratio of Fe to H₂ is 3:4.
  3. The molar mass of H₂ is 2.02 g/mol.

5.25gH_2 \times \frac{1molH_2}{2.02gH_2} \times\frac{3molFe}{4molH_2} \times\frac{55.85gFe}{1molFe} = 109gFe

Considering the given reaction, 109 g of Fe are needed to generate 5.25 g of H₂.

Learn more about stoichiometry here: brainly.com/question/16060223

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Let p_1, v_1, and T_1 be the initial and p_2, v_2, and T_2 be the final pressure, volume, and temperature of the gas respectively.

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From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)

For the final condition,

p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)

Equating equation (i), and (ii)

\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}

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in yr language:

Ang Holy Roman Empire (Latin: Sacrum Imperium Romanum; German: Heiliges Römisches Reich), na tinawag din bilang First Reich, ay isang multi-etniko na kumplikado ng mga teritoryo sa Kanluran at Gitnang Europa na d

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