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Mumz [18]
2 years ago
7

How many grams of iron (Fe) would be needed to generate 5.25 g of hydrogen gas (H2)?

Chemistry
1 answer:
Free_Kalibri [48]2 years ago
8 0

Considering the given reaction, 109 g of Fe are needed to generate 5.25 g of H₂.

<h3>What is stoichiometry?</h3>

Stoichiometry refers to the relationship between the quantities of reactants and products before, during, and following chemical reactions.

  • Step 1: Write the balanced equation.

3 Fe + 4 H₂O ⇒ 4 H₂ + Fe₃O₄

  • Step 2: Calculate the mass of Fe needed to produce 5.25 g of H₂.

We will consider the following relationships.

  1. The molar mass of Fe is 55.85 g/mol.
  2. The molar ratio of Fe to H₂ is 3:4.
  3. The molar mass of H₂ is 2.02 g/mol.

5.25gH_2 \times \frac{1molH_2}{2.02gH_2} \times\frac{3molFe}{4molH_2} \times\frac{55.85gFe}{1molFe} = 109gFe

Considering the given reaction, 109 g of Fe are needed to generate 5.25 g of H₂.

Learn more about stoichiometry here: brainly.com/question/16060223

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These gases all have similar properties under standard conditions: they are all odorless, colorless, monatomic gases with very low chemical reactivity. The six noble gases that occur naturally are helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), and Radon (Rn).
6 0
3 years ago
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A 2.000 g sample of CoCl2.xH2O is dried in an oven. When the anhydrous salt is removed from the oven, its mass is 1.565 g. What
Mashutka [201]

The value of X is 2

The total amount of sample taken is 2.00 g

The amount of sample left in the oven after drying is 1.565g

The amount of sample lost (mass of water driven out) = Total sample-Anhydrous salt left in the oven

                                 = 2.00 - 1.565

                                = 0.435 grams

The moles of anhydrous salt present in the hydrate = 1.565g/129.83g/mol = 0.01205

The moles of water present in the hydrate = 0.4350g/18.01g/mol = 0.02415

Therefore the ratio of these two are in 1:2 ratio

The complete chemical reaction is   CoCl2.2H20

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6 0
9 months ago
Write the equilibrium constant expression for this reaction: nh4
pochemuha
Kc= (nh4)
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(nh3) + (h2o)
4 0
3 years ago
imagine that you go into the lab and perform a titration. you measure 40 ml of your analyte and add it to an erlenmeyer flask. t
mote1985 [20]

The Molar concentration of your analyte solution is 1.17 m

<h3>What is titration reaction?</h3>
  • Titration is a chemical analysis procedure that determines the amount of a sample's ingredient by adding a precisely known amount of another substance to the measured sample, with which the desired constituent reacts in a specific, known proportion.

Make use of the titration formula.

The formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base.

if the titrant and analyte have a 1:1 mole ratio. (Molarity is a measure of a solution's concentration represented as the number of moles of solute per litre of solution.)

26 x 1.8 = 40 x M

M = 26 x1.8 /40

M = 1.17

The Molar concentration of your analyte solution is 1.17 m

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5 0
1 year ago
What mass of Ca(NO3)2 is equal to 0.75 moles of this substance?
sattari [20]

Answer:

Ca - 63.546 g

2N - 28.014 g

2O3 - 96 g

Ca(NO3)2 = 187.56 g

187.56 g x 0.75 mol = 140.67 g

Explanation:

Hope this helps

5 0
2 years ago
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